- The curve \(C\) has equation \(y = \mathrm { f } ( x )\) where
$$f ( x ) = \frac { 4 x + 1 } { x - 2 } , \quad x > 2$$
- Show that
$$f ^ { \prime } ( x ) = \frac { - 9 } { ( x - 2 ) ^ { 2 } }$$
Given that \(P\) is a point on \(C\) such that \(\mathrm { f } ^ { \prime } ( x ) = - 1\),
- find the coordinates of \(P\).