Edexcel C3 2008 January — Question 4 10 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Year2008
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeTransformations of modulus graphs from given f(x) sketch
DifficultyModerate -0.8 This is a standard C3 transformations question requiring application of well-defined rules for modulus and function transformations. Students need to recall and apply three routine transformation types with no problem-solving or novel insight required—purely procedural execution of learned techniques.
Spec1.02s Modulus graphs: sketch graph of |ax+b|1.02w Graph transformations: simple transformations of f(x)

4. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{a15db39c-d54b-4cf4-8da7-01f3db223415-05_735_1171_223_390} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows a sketch of the curve with equation \(y = \mathrm { f } ( x )\).
The curve passes through the origin \(O\) and the points \(A ( 5,4 )\) and \(B ( - 5 , - 4 )\).
In separate diagrams, sketch the graph with equation
  1. \(y = | f ( x ) |\),
  2. \(y = \mathrm { f } ( | x | )\),
  3. \(y = 2 f ( x + 1 )\). On each sketch, show the coordinates of the points corresponding to \(A\) and \(B\).

Question 4:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Correct shape (W-shape reflected)B1
Point \((5, 4)\) markedB1
Point \((-5, 4)\) markedB1
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Graph identical to (a); shapeB1 For marking purposes graph is identical to (a)
\((5, 4)\)B1
\((-5, 4)\)B1
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
General shape unchangedB1
Translation to leftB1
\((4, 8)\) markedB1
\((-6, -8)\) markedB1
# Question 4:

## Part (a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Correct shape (W-shape reflected) | B1 | |
| Point $(5, 4)$ marked | B1 | |
| Point $(-5, 4)$ marked | B1 | |

## Part (b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Graph identical to (a); shape | B1 | For marking purposes graph is identical to (a) |
| $(5, 4)$ | B1 | |
| $(-5, 4)$ | B1 | |

## Part (c):

| Answer/Working | Marks | Guidance |
|---|---|---|
| General shape unchanged | B1 | |
| Translation to left | B1 | |
| $(4, 8)$ marked | B1 | |
| $(-6, -8)$ marked | B1 | |

---
4.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{a15db39c-d54b-4cf4-8da7-01f3db223415-05_735_1171_223_390}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

Figure 1 shows a sketch of the curve with equation $y = \mathrm { f } ( x )$.\\
The curve passes through the origin $O$ and the points $A ( 5,4 )$ and $B ( - 5 , - 4 )$.\\
In separate diagrams, sketch the graph with equation
\begin{enumerate}[label=(\alph*)]
\item $y = | f ( x ) |$,
\item $y = \mathrm { f } ( | x | )$,
\item $y = 2 f ( x + 1 )$.

On each sketch, show the coordinates of the points corresponding to $A$ and $B$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3 2008 Q4 [10]}}