Edexcel C3 2008 January — Question 2 8 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Year2008
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProduct & Quotient Rules
TypeShow derivative satisfies condition
DifficultyStandard +0.3 This is a straightforward application of the product rule with standard derivatives (e^(2x) and tan x). Part (a) requires setting dy/dx = 0 and simple algebraic manipulation. Part (b) is routine tangent line calculation. Slightly above average difficulty due to the product rule with exponential and trig functions, but still a standard textbook exercise with no novel insight required.
Spec1.07j Differentiate exponentials: e^(kx) and a^(kx)1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)1.07m Tangents and normals: gradient and equations1.07q Product and quotient rules: differentiation

2. A curve \(C\) has equation $$y = \mathrm { e } ^ { 2 x } \tan x , \quad x \neq ( 2 n + 1 ) \frac { \pi } { 2 }$$
  1. Show that the turning points on \(C\) occur where \(\tan x = - 1\).
  2. Find an equation of the tangent to \(C\) at the point where \(x = 0\).

Question 2:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{dy}{dx} = 2e^{2x}\tan x + e^{2x}\sec^2 x\)M1 A1+A1
\(\frac{dy}{dx} = 0 \Rightarrow 2e^{2x}\tan x + e^{2x}\sec^2 x = 0\)M1
\(2\tan x + 1 + \tan^2 x = 0\)A1
\((\tan x + 1)^2 = 0\)
\(\tan x = -1\)A1 cso
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\left(\frac{dy}{dx}\right)_0 = 1\)M1
Equation of tangent at \((0,0)\) is \(y = x\)A1
# Question 2:

## Part (a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{dy}{dx} = 2e^{2x}\tan x + e^{2x}\sec^2 x$ | M1 A1+A1 | |
| $\frac{dy}{dx} = 0 \Rightarrow 2e^{2x}\tan x + e^{2x}\sec^2 x = 0$ | M1 | |
| $2\tan x + 1 + \tan^2 x = 0$ | A1 | |
| $(\tan x + 1)^2 = 0$ | | |
| $\tan x = -1$ | A1 | cso |

## Part (b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\left(\frac{dy}{dx}\right)_0 = 1$ | M1 | |
| Equation of tangent at $(0,0)$ is $y = x$ | A1 | |

---
2. A curve $C$ has equation

$$y = \mathrm { e } ^ { 2 x } \tan x , \quad x \neq ( 2 n + 1 ) \frac { \pi } { 2 }$$
\begin{enumerate}[label=(\alph*)]
\item Show that the turning points on $C$ occur where $\tan x = - 1$.
\item Find an equation of the tangent to $C$ at the point where $x = 0$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3 2008 Q2 [8]}}