Edexcel C34 2016 January — Question 10 12 marks

Exam BoardEdexcel
ModuleC34 (Core Mathematics 3 & 4)
Year2016
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard harmonic form question with routine techniques: converting to R sin(θ+α) using Pythagorean identity and arctan, solving a basic trigonometric equation, and finding max/min values using the range of sine. All steps are textbook procedures with no novel insight required, making it slightly easier than average.
Spec1.02w Graph transformations: simple transformations of f(x)1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

10. (a) Express \(3 \sin 2 x + 5 \cos 2 x\) in the form \(R \sin ( 2 x + \alpha )\), where \(R > 0\) and \(0 < \alpha < \frac { \pi } { 2 }\) Give the exact value of \(R\) and give the value of \(\alpha\) to 3 significant figures.
(b) Solve, for \(0 < x < \pi\), $$3 \sin 2 x + 5 \cos 2 x = 4$$ (Solutions based entirely on graphical or numerical methods are not acceptable.) $$g ( x ) = 4 ( 3 \sin 2 x + 5 \cos 2 x ) ^ { 2 } + 3$$ (c) Using your answer to part (a) and showing your working,
  1. find the greatest value of \(\mathrm { g } ( x )\),
  2. find the least value of \(\mathrm { g } ( x )\).

Question 10(a) - R-alpha Form
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(R = \sqrt{34}\)B1 Condone \(\pm\sqrt{34}\)
\(\tan\alpha = \dfrac{5}{3}\)M1 Or \(\tan\alpha=\pm\dfrac{5}{3}\) or \(\pm\dfrac{3}{5}\); implied by awrt 1.0 rads or 59°
\(\alpha = 1.03\)A1 awrt 1.03; also accept \(\sqrt{34}\sin(2x+1.03)\); degrees answer (59.04) is A0
Question 10(b) - Solving Equation
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\sin(2x+\text{"1.03"}) = \dfrac{4}{\text{"}\sqrt{34}\text{"}}\) \((=0.68599...)\)M1 Uses part (a) to solve equation
\(2x+\text{"1.03"}=2\pi+\arcsin\left(\dfrac{4}{\text{"}\sqrt{34}\text{"}}\right)\Rightarrow x=...\)M1 Attempt at one solution in range; acceptable to find \(-0.14\) and add \(\pi\)
Either \(x=\) awrt 3.0 or awrt 0.68A1 In degrees accept awrt 38.8 or 172.1; condone 3 for 3.0
\(2x+\text{"1.03"}=\pi-\arcsin\left(\dfrac{4}{\text{"}\sqrt{34}\text{"}}\right)\Rightarrow x=...\)M1 Attempt at second solution
Both \(x=\) awrt 3.0 and awrt 0.68A1 In degrees awrt 38.8 and awrt 172.1; condone 3 for 3.0
Question 10(c) - Greatest/Least Values
AnswerMarks Guidance
Answer/WorkingMark Guidance
Greatest value: \(4(\sqrt{34})^2+3 = 139\)M1 A1 Attempts \(4(R)^2+3\); cao
Least value: \(4(0)^2+3 = 3\)M1 A1 Uses 0 for minimum value; accept \(4(0)^2+3\)
# Question 10(a) - R-alpha Form

| Answer/Working | Mark | Guidance |
|---|---|---|
| $R = \sqrt{34}$ | B1 | Condone $\pm\sqrt{34}$ |
| $\tan\alpha = \dfrac{5}{3}$ | M1 | Or $\tan\alpha=\pm\dfrac{5}{3}$ or $\pm\dfrac{3}{5}$; implied by awrt 1.0 rads or 59° |
| $\alpha = 1.03$ | A1 | awrt 1.03; also accept $\sqrt{34}\sin(2x+1.03)$; degrees answer (59.04) is A0 |

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# Question 10(b) - Solving Equation

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\sin(2x+\text{"1.03"}) = \dfrac{4}{\text{"}\sqrt{34}\text{"}}$ $(=0.68599...)$ | M1 | Uses part (a) to solve equation |
| $2x+\text{"1.03"}=2\pi+\arcsin\left(\dfrac{4}{\text{"}\sqrt{34}\text{"}}\right)\Rightarrow x=...$ | M1 | Attempt at one solution in range; acceptable to find $-0.14$ and add $\pi$ |
| Either $x=$ awrt 3.0 **or** awrt 0.68 | A1 | In degrees accept awrt 38.8 or 172.1; condone 3 for 3.0 |
| $2x+\text{"1.03"}=\pi-\arcsin\left(\dfrac{4}{\text{"}\sqrt{34}\text{"}}\right)\Rightarrow x=...$ | M1 | Attempt at second solution |
| Both $x=$ awrt 3.0 **and** awrt 0.68 | A1 | In degrees awrt 38.8 and awrt 172.1; condone 3 for 3.0 |

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# Question 10(c) - Greatest/Least Values

| Answer/Working | Mark | Guidance |
|---|---|---|
| Greatest value: $4(\sqrt{34})^2+3 = 139$ | M1 A1 | Attempts $4(R)^2+3$; cao |
| Least value: $4(0)^2+3 = 3$ | M1 A1 | Uses 0 for minimum value; accept $4(0)^2+3$ |
10. (a) Express $3 \sin 2 x + 5 \cos 2 x$ in the form $R \sin ( 2 x + \alpha )$, where $R > 0$ and $0 < \alpha < \frac { \pi } { 2 }$ Give the exact value of $R$ and give the value of $\alpha$ to 3 significant figures.\\
(b) Solve, for $0 < x < \pi$,

$$3 \sin 2 x + 5 \cos 2 x = 4$$

(Solutions based entirely on graphical or numerical methods are not acceptable.)

$$g ( x ) = 4 ( 3 \sin 2 x + 5 \cos 2 x ) ^ { 2 } + 3$$

(c) Using your answer to part (a) and showing your working,
\begin{enumerate}[label=(\roman*)]
\item find the greatest value of $\mathrm { g } ( x )$,
\item find the least value of $\mathrm { g } ( x )$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C34 2016 Q10 [12]}}