Edexcel P3 2020 January — Question 1 6 marks

Exam BoardEdexcel
ModuleP3 (Pure Mathematics 3)
Year2020
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Functions
TypeLogistic growth model
DifficultyStandard +0.3 This is a straightforward logistic growth question requiring: (a) substitution of t=0, (b) solving an exponential equation using logarithms (standard technique), and (c) finding the horizontal asymptote by considering the limit as t→∞. All parts use routine A-level techniques with no novel insight required, making it slightly easier than average.
Spec1.06g Equations with exponentials: solve a^x = b1.06i Exponential growth/decay: in modelling context

  1. A population of a rare species of toad is being studied.
The number of toads, \(N\), in the population, \(t\) years after the start of the study, is modelled by the equation $$N = \frac { 900 \mathrm { e } ^ { 0.12 t } } { 2 \mathrm { e } ^ { 0.12 t } + 1 } \quad t \geqslant 0 , t \in \mathbb { R }$$ According to this model,
  1. calculate the number of toads in the population at the start of the study,
  2. find the value of \(t\) when there are 420 toads in the population, giving your answer to 2 decimal places.
  3. Explain why, according to this model, the number of toads in the population can never reach 500

AnswerMarks Guidance
(a) \(P_0 = 300\)B1 (1)
(b) \(420 = \frac{900e^{0.12t}}{2e^{0.12t}+1} \Rightarrow 60e^{0.12t} = 420\)M1 A1
Correct use of lns \(\Rightarrow t = \frac{\ln 7}{0.12} = 16.22\)dM1 A1 (4)
(c) States that maximum number (upper limit) is 450 so cannot reach 500B1 (1)
Total: 6 marks
**(a)** $P_0 = 300$ | B1 | (1)

**(b)** $420 = \frac{900e^{0.12t}}{2e^{0.12t}+1} \Rightarrow 60e^{0.12t} = 420$ | M1 A1 | 
Correct use of lns $\Rightarrow t = \frac{\ln 7}{0.12} = 16.22$ | dM1 A1 | (4)

**(c)** States that maximum number (upper limit) is 450 so cannot reach 500 | B1 | (1)

**Total: 6 marks**

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\begin{enumerate}
  \item A population of a rare species of toad is being studied.
\end{enumerate}

The number of toads, $N$, in the population, $t$ years after the start of the study, is modelled by the equation

$$N = \frac { 900 \mathrm { e } ^ { 0.12 t } } { 2 \mathrm { e } ^ { 0.12 t } + 1 } \quad t \geqslant 0 , t \in \mathbb { R }$$

According to this model,\\
(a) calculate the number of toads in the population at the start of the study,\\
(b) find the value of $t$ when there are 420 toads in the population, giving your answer to 2 decimal places.\\
(c) Explain why, according to this model, the number of toads in the population can never reach 500

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\hfill \mbox{\textit{Edexcel P3 2020 Q1 [6]}}