CAIE P1 2011 November — Question 10 10 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2011
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeSum of first n terms
DifficultyModerate -0.8 This is a straightforward multi-part question testing standard arithmetic progression formulas (sum, nth term) and basic geometric progression calculations. Part (a) requires direct application of S_n and a_n formulas with minimal problem-solving, while part (b) is routine compound interest/GP work. All techniques are textbook exercises with clear pathways and no novel insight required.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum

10
  1. An arithmetic progression contains 25 terms and the first term is - 15 . The sum of all the terms in the progression is 525. Calculate
    1. the common difference of the progression,
    2. the last term in the progression,
    3. the sum of all the positive terms in the progression.
  2. A college agrees a sponsorship deal in which grants will be received each year for sports equipment. This grant will be \(\\) 4000\( in 2012 and will increase by \)5 \%$ each year. Calculate
    1. the value of the grant in 2022,
    2. the total amount the college will receive in the years 2012 to 2022 inclusive.

(a)
- M1: \(a = -15\), \(n = 25\). Must be correct formula. co
- A1: Use of \(S_n \Rightarrow d = 3\)
(i)
- M1: Last term \(= a + 24d\). Must be \(a + 24d\)
- A1: \(\Rightarrow 57\) (or \(525 = \frac{1}{2} \times 25 \times (-15 + l) \Rightarrow l = 57\)). \(\checkmark\) for his \(d\)
(ii)
- M1: Positive terms are \(3, 6, \ldots, 57\). Either \(a = 0\) or \(3\), \(n = 19\) or \(20\)
- A1: Use of \(S_{19}\) or \(S_{20}\) \(\Rightarrow 570\). Correct use of formula for \(S_n\)
(b)
- B1: \(r = 1.05\). co
- B1: In either part (i) or (ii)
(i)
- M1: \(11\)th term \(= ar^{10} = \\)6516\( or \)\\(6520\). co
- A1: co
(ii)
- M1: \(S_{11} = \frac{4000 \times (1.05^{11} - 1)}{0.05}\). Correct sum formula with their \(r\)
- A1: \(= \\)56800\( or \)(56827)$. co
**(a)**
- M1: $a = -15$, $n = 25$. Must be correct formula. co
- A1: Use of $S_n \Rightarrow d = 3$

**(i)**
- M1: Last term $= a + 24d$. Must be $a + 24d$
- A1: $\Rightarrow 57$ (or $525 = \frac{1}{2} \times 25 \times (-15 + l) \Rightarrow l = 57$). $\checkmark$ for his $d$

**(ii)**
- M1: Positive terms are $3, 6, \ldots, 57$. Either $a = 0$ or $3$, $n = 19$ or $20$
- A1: Use of $S_{19}$ or $S_{20}$ $\Rightarrow 570$. Correct use of formula for $S_n$

**(b)**
- B1: $r = 1.05$. co
- B1: In either part (i) or (ii)

**(i)**
- M1: $11$th term $= ar^{10} = \$6516$ or $\$6520$. co
- A1: co

**(ii)**
- M1: $S_{11} = \frac{4000 \times (1.05^{11} - 1)}{0.05}$. Correct sum formula with their $r$
- A1: $= \$56800$ or $(56827)$. co
10
\begin{enumerate}[label=(\alph*)]
\item An arithmetic progression contains 25 terms and the first term is - 15 . The sum of all the terms in the progression is 525. Calculate
\begin{enumerate}[label=(\roman*)]
\item the common difference of the progression,
\item the last term in the progression,
\item the sum of all the positive terms in the progression.
\end{enumerate}\item A college agrees a sponsorship deal in which grants will be received each year for sports equipment. This grant will be $\$ 4000$ in 2012 and will increase by $5 \%$ each year. Calculate
\begin{enumerate}[label=(\roman*)]
\item the value of the grant in 2022,
\item the total amount the college will receive in the years 2012 to 2022 inclusive.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2011 Q10 [10]}}