CAIE P1 2011 November — Question 1 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2011
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeSubstitution into binomial expansion
DifficultyModerate -0.3 Part (i) is a straightforward binomial expansion with small integer power requiring only formula application. Part (ii) involves substitution and collecting terms, which adds a modest problem-solving element, but the overall question remains routine for A-level with clear signposting and limited algebraic complexity.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

1
  1. Find the first 3 terms in the expansion of \(( 2 - y ) ^ { 5 }\) in ascending powers of \(y\).
  2. Use the result in part (i) to find the coefficient of \(x ^ { 2 }\) in the expansion of \(\left( 2 - \left( 2 x - x ^ { 2 } \right) \right) ^ { 5 }\).

Question 1:
(i) \((2-y)^5 = 32 - 80y + 80y^2\)
B2,1
[2]
(ii) \((2-(2x-x^2))^5\) where \(y = 2x - x^2\)
M1
\(80 + 320 = 400\)
M1
A1
[3]
Guidance:
\(-1\) for each error. Accept \(\frac{5}{2}\).
Allow for \(y = 2x + x^2\)
Needs to consider exactly 2 terms.
\(400x^2\) — accept if \(\frac{400x^2}{...}\) is part of it, accept full expansion.
Question 1:

(i) $(2-y)^5 = 32 - 80y + 80y^2$
B2,1
[2]

(ii) $(2-(2x-x^2))^5$ where $y = 2x - x^2$
M1

$80 + 320 = 400$
M1
A1
[3]

**Guidance:**
$-1$ for each error. Accept $\frac{5}{2}$.
Allow for $y = 2x + x^2$
Needs to consider exactly 2 terms.
$400x^2$ — accept if $\frac{400x^2}{...}$ is part of it, accept full expansion.
1 (i) Find the first 3 terms in the expansion of $( 2 - y ) ^ { 5 }$ in ascending powers of $y$.\\
(ii) Use the result in part (i) to find the coefficient of $x ^ { 2 }$ in the expansion of $\left( 2 - \left( 2 x - x ^ { 2 } \right) \right) ^ { 5 }$.

\hfill \mbox{\textit{CAIE P1 2011 Q1 [5]}}