Edexcel P2 2023 October — Question 2 5 marks

Exam BoardEdexcel
ModuleP2 (Pure Mathematics 2)
Year2023
SessionOctober
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeSimple recurrence evaluation
DifficultyModerate -0.3 Part (a) requires straightforward substitution into a recurrence relation (3 iterations), and part (b) requires recognizing the sequence alternates between two values (3 and -2), making the sum a simple arithmetic calculation. This is easier than average as it involves only direct computation and pattern recognition, with no proof or novel problem-solving required.
Spec1.04e Sequences: nth term and recurrence relations1.04g Sigma notation: for sums of series

  1. A sequence \(u _ { 1 } , u _ { 2 } , u _ { 3 } , \ldots\) is defined by
$$\begin{gathered} u _ { 1 } = 3 \\ u _ { n + 1 } = 2 - \frac { 4 } { u _ { n } } \end{gathered}$$
  1. Find the value of \(u _ { 2 }\), the value of \(u _ { 3 }\) and the value of \(u _ { 4 }\)
  2. Find the value of $$\sum _ { r = 1 } ^ { 100 } u _ { r }$$

Question 2:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Attempts iteration formula at least once: \(u_{1+1}=2-\frac{4}{3}=\ldots\)M1 Implied by correct value on correct term, or correct follow-through value
Any one correct value on correct term: \(u_2=\frac{2}{3}\) (condone 0.67) or \(u_3=-4\) or \(u_4=3\)A1 Watch for correct values on wrong terms
All three correct and labelled: \(u_2=\frac{2}{3}\), \(u_3=-4\), \(u_4=3\)A1 May be awarded from part (b)
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\displaystyle\sum_{r=1}^{100}u_r = 33\times\left(3+\frac{2}{3}+(-4)\right)+3\)M1 Correct method to find sum of 100 terms; listing acceptable only if all terms present or correct result given
\(= -8\)A1 \(-8\) alone scores both marks following correct (a), provided no incorrect method
# Question 2:

## Part (a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Attempts iteration formula at least once: $u_{1+1}=2-\frac{4}{3}=\ldots$ | M1 | Implied by correct value on correct term, or correct follow-through value |
| Any one correct value on correct term: $u_2=\frac{2}{3}$ (condone 0.67) or $u_3=-4$ or $u_4=3$ | A1 | Watch for correct values on wrong terms |
| All three correct and labelled: $u_2=\frac{2}{3}$, $u_3=-4$, $u_4=3$ | A1 | May be awarded from part (b) |

## Part (b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\displaystyle\sum_{r=1}^{100}u_r = 33\times\left(3+\frac{2}{3}+(-4)\right)+3$ | M1 | Correct method to find sum of 100 terms; listing acceptable only if all terms present or correct result given |
| $= -8$ | A1 | $-8$ alone scores both marks following correct (a), provided no incorrect method |

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\begin{enumerate}
  \item A sequence $u _ { 1 } , u _ { 2 } , u _ { 3 } , \ldots$ is defined by
\end{enumerate}

$$\begin{gathered}
u _ { 1 } = 3 \\
u _ { n + 1 } = 2 - \frac { 4 } { u _ { n } }
\end{gathered}$$

(a) Find the value of $u _ { 2 }$, the value of $u _ { 3 }$ and the value of $u _ { 4 }$\\
(b) Find the value of

$$\sum _ { r = 1 } ^ { 100 } u _ { r }$$

\hfill \mbox{\textit{Edexcel P2 2023 Q2 [5]}}