CAIE P1 2010 November — Question 6 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeLine-curve intersection conditions
DifficultyModerate -0.3 This is a standard discriminant problem requiring students to set equations equal, form a quadratic, and apply b²-4ac < 0 for no intersection. Part (ii) extends to the tangency condition (discriminant = 0). While it involves multiple steps and careful algebraic manipulation, it's a routine textbook exercise on a core AS-level topic with no novel insight required, making it slightly easier than average.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02f Solve quadratic equations: including in a function of unknown1.07m Tangents and normals: gradient and equations

6 A curve has equation \(y = k x ^ { 2 } + 1\) and a line has equation \(y = k x\), where \(k\) is a non-zero constant.
  1. Find the set of values of \(k\) for which the curve and the line have no common points.
  2. State the value of \(k\) for which the line is a tangent to the curve and, for this case, find the coordinates of the point where the line touches the curve.

Question 6:
Part (i)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(kx^2 - kx + 1 = 0\)M1 \(y\) eliminated
\(k^2 - 4k < 0\)M1 Applying \(b^2 - 4ac < 0\) or \(=\) or \(\leq\) or \(\geq\)
\(0 < k < 4\)A1 co
Part (ii)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(k = 4\) onlyB1\(\sqrt{}\) ft from their \(k^2 - 4k = 0\) (Not \(k=0\))
\((2x-1)^2 = 0\)M1 ft from their \(k\)
\(x = \frac{1}{2},\ y = 2\) or \((\frac{1}{2}, 2)\)A1, A1
## Question 6:

**Part (i)**

| Answer/Working | Marks | Guidance |
|---|---|---|
| $kx^2 - kx + 1 = 0$ | M1 | $y$ eliminated |
| $k^2 - 4k < 0$ | M1 | Applying $b^2 - 4ac < 0$ or $=$ or $\leq$ or $\geq$ |
| $0 < k < 4$ | A1 | co |

**Part (ii)**

| Answer/Working | Marks | Guidance |
|---|---|---|
| $k = 4$ only | B1$\sqrt{}$ | ft from their $k^2 - 4k = 0$ (Not $k=0$) |
| $(2x-1)^2 = 0$ | M1 | ft from their $k$ |
| $x = \frac{1}{2},\ y = 2$ or $(\frac{1}{2}, 2)$ | A1, A1 | |

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6 A curve has equation $y = k x ^ { 2 } + 1$ and a line has equation $y = k x$, where $k$ is a non-zero constant.\\
(i) Find the set of values of $k$ for which the curve and the line have no common points.\\
(ii) State the value of $k$ for which the line is a tangent to the curve and, for this case, find the coordinates of the point where the line touches the curve.

\hfill \mbox{\textit{CAIE P1 2010 Q6 [7]}}