CAIE P1 2009 November — Question 4 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2009
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeRange from trigonometric functions
DifficultyModerate -0.8 This is a straightforward question on trigonometric functions requiring knowledge that sin ranges from -1 to 1, basic graph sketching of a transformed sine curve, and understanding of the horizontal line test for inverses. All parts are routine applications of standard techniques with no problem-solving insight required.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

4 The function f is defined by f : \(x \mapsto 5 - 3 \sin 2 x\) for \(0 \leqslant x \leqslant \pi\).
  1. Find the range of f .
  2. Sketch the graph of \(y = \mathrm { f } ( x )\).
  3. State, with a reason, whether f has an inverse.

AnswerMarks Guidance
(i) \(2 \leq f(x) \leq 8\)B1, B1 [2] B1 for 2, B1 for 8. Must be stated, not on graph.
(ii) \(x \mapsto 5 - 3\sin 2x\)B1, DB1, B1 [3] 1 complete oscillation. 1st quadrant, not touching x-axis. Needs to be "down" first and curves. nb If no labels, assume 0 to \(\pi\).
(iii) No inverse – not 1 : 1.B1 [1] co. Independent of graph.
Total: [6]
**(i)** $2 \leq f(x) \leq 8$ | B1, B1 [2] | B1 for 2, B1 for 8. Must be stated, not on graph.

**(ii)** $x \mapsto 5 - 3\sin 2x$ | B1, DB1, B1 [3] | 1 complete oscillation. 1st quadrant, not touching x-axis. Needs to be "down" first and curves. nb If no labels, assume 0 to $\pi$.

**(iii)** No inverse – not 1 : 1. | B1 [1] | co. Independent of graph.

**Total: [6]**

---
4 The function f is defined by f : $x \mapsto 5 - 3 \sin 2 x$ for $0 \leqslant x \leqslant \pi$.\\
(i) Find the range of f .\\
(ii) Sketch the graph of $y = \mathrm { f } ( x )$.\\
(iii) State, with a reason, whether f has an inverse.

\hfill \mbox{\textit{CAIE P1 2009 Q4 [6]}}