Edexcel C1 2010 January — Question 8 7 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2010
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeSketch single transformation from given curve
DifficultyModerate -0.8 This is a straightforward C1 transformation question requiring application of standard rules (vertical translation, vertical stretch, horizontal translation) to a given curve. Students need only apply memorized transformation rules to find new coordinates and asymptote equations—no problem-solving or conceptual insight required. Easier than average due to its routine, mechanical nature.
Spec1.02w Graph transformations: simple transformations of f(x)

8. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{280f0f3b-fdb5-4ac9-adc6-150819b03539-10_646_986_246_562} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows a sketch of part of the curve with equation \(y = \mathrm { f } ( x )\).
The curve has a maximum point \(( - 2,5 )\) and an asymptote \(y = 1\), as shown in Figure 1. On separate diagrams, sketch the curve with equation
  1. \(y = \mathrm { f } ( x ) + 2\)
  2. \(y = 4 \mathrm { f } ( x )\)
  3. \(y = \mathrm { f } ( \mathrm { x } + 1 )\) On each diagram, show clearly the coordinates of the maximum point and the equation of the asymptote.

Question 8:
(a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Maximum \((-2, 7)\), asymptote \(y = 3\)B1, B1 Marks dependent on sketch being attempted. Both max coordinates correct and asymptote equation required
(b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Maximum \((-2, 20)\), asymptote \(y = 4\)B1, B1 Marks dependent on sketch being attempted
(c)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Horizontal translation sketchB1 Evidence that \(y=5\) at max and asymptote is still \(y=1\)
Maximum \((-3, 5)\), asymptote \(y = 1\)B1, B1
## Question 8:

**(a)**

| Answer/Working | Marks | Guidance |
|---|---|---|
| Maximum $(-2, 7)$, asymptote $y = 3$ | B1, B1 | Marks dependent on sketch being attempted. Both max coordinates correct and asymptote equation required |

**(b)**

| Answer/Working | Marks | Guidance |
|---|---|---|
| Maximum $(-2, 20)$, asymptote $y = 4$ | B1, B1 | Marks dependent on sketch being attempted |

**(c)**

| Answer/Working | Marks | Guidance |
|---|---|---|
| Horizontal translation sketch | B1 | Evidence that $y=5$ at max and asymptote is still $y=1$ |
| Maximum $(-3, 5)$, asymptote $y = 1$ | B1, B1 | |

---
8.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{280f0f3b-fdb5-4ac9-adc6-150819b03539-10_646_986_246_562}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

Figure 1 shows a sketch of part of the curve with equation $y = \mathrm { f } ( x )$.\\
The curve has a maximum point $( - 2,5 )$ and an asymptote $y = 1$, as shown in Figure 1.

On separate diagrams, sketch the curve with equation
\begin{enumerate}[label=(\alph*)]
\item $y = \mathrm { f } ( x ) + 2$
\item $y = 4 \mathrm { f } ( x )$
\item $y = \mathrm { f } ( \mathrm { x } + 1 )$

On each diagram, show clearly the coordinates of the maximum point and the equation of the asymptote.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1 2010 Q8 [7]}}