Edexcel C12 2017 October — Question 13 9 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2017
SessionOctober
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircles
TypePoint position relative to circle
DifficultyModerate -0.8 This is a straightforward circle question requiring basic recall of circle equation form (parts a(i) and a(ii)), substitution of a point into the inequality for points inside a circle (part b), and solving a quadratic inequality (part c). All steps are routine Core 1/2 techniques with no problem-solving insight required, making it easier than average but not trivial due to the multi-part structure.
Spec1.02g Inequalities: linear and quadratic in single variable1.03d Circles: equation (x-a)^2+(y-b)^2=r^2

  1. The circle \(C\) has equation
$$( x - 3 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 30$$ Write down
    1. the coordinates of the centre of \(C\),
    2. the exact value of the radius of \(C\). Given that the point \(P\) with coordinates \(( 6 , k )\), where \(k\) is a constant, lies inside circle \(C\), (b) show that $$k ^ { 2 } + 8 k - 5 < 0$$
  1. Hence find the exact set of values of \(k\) for which \(P\) lies inside \(C\). \includegraphics[max width=\textwidth, alt={}, center]{bb1becd5-96c1-426d-9b85-4bbc4a61af27-34_2256_52_315_1978}

Question 13:
Part (a)(i):
AnswerMarks Guidance
AnswerMarks Guidance
\((3,-4)\)B1 Accept as \(x=\) , \(y=\) or even without brackets
Part (a)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\sqrt{30}\)B1 [2] Do not accept decimals
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
Attempts \((6-3)^2+(k+4)^2 < 30\)M1, M1 M1: attempts length or length² from \(P(6,k)\) to centre \(C(3,-4)\); M1: forms inequality using length from \(P\) to centre \(< \) radius
\(k^2+8k-5<0\)A1* [3] Given answer; must see intermediate line with \(<30\) before \(<0\)
Part (c):
AnswerMarks Guidance
AnswerMarks Guidance
Solves \(k^2+8k-5=0\) by formula or completing the squareM1 Factorisation to integer roots not suitable; answers could just appear from graphical calculator; accept decimals for M marks only
\(k=-4\pm\sqrt{21}\)A1 Accept \(k=-4\pm\sqrt{21}\) or exact equivalent \(k=\frac{-8\pm\sqrt{84}}{2}\); do not accept decimal equivalents \(k=-8.58, (+)0.58\) for this mark
Chooses region between two valuesM1 Chooses inside region from their two roots
\(-4-\sqrt{21} < k < -4+\sqrt{21}\)A1cao [4] Accept equivalents such as \((-4-\sqrt{21}, -4+\sqrt{21})\); do not accept \(-4-\sqrt{21}
# Question 13:

## Part (a)(i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $(3,-4)$ | B1 | Accept as $x=$ , $y=$ or even without brackets |

## Part (a)(ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\sqrt{30}$ | B1 [2] | Do not accept decimals |

## Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempts $(6-3)^2+(k+4)^2 < 30$ | M1, M1 | M1: attempts length or length² from $P(6,k)$ to centre $C(3,-4)$; M1: forms inequality using length from $P$ to centre $< $ radius |
| $k^2+8k-5<0$ | A1* [3] | Given answer; must see intermediate line with $<30$ before $<0$ |

## Part (c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Solves $k^2+8k-5=0$ by formula or completing the square | M1 | Factorisation to integer roots not suitable; answers could just appear from graphical calculator; accept decimals for M marks only |
| $k=-4\pm\sqrt{21}$ | A1 | Accept $k=-4\pm\sqrt{21}$ or exact equivalent $k=\frac{-8\pm\sqrt{84}}{2}$; do not accept decimal equivalents $k=-8.58, (+)0.58$ for this mark |
| Chooses region between two values | M1 | Chooses inside region from their two roots |
| $-4-\sqrt{21} < k < -4+\sqrt{21}$ | A1cao [4] | Accept equivalents such as $(-4-\sqrt{21}, -4+\sqrt{21})$; do not accept $-4-\sqrt{21}<x<-4+\sqrt{21}$ for final mark |

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\begin{enumerate}
  \item The circle $C$ has equation
\end{enumerate}

$$( x - 3 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 30$$

Write down\\
(a) (i) the coordinates of the centre of $C$,\\
(ii) the exact value of the radius of $C$.

Given that the point $P$ with coordinates $( 6 , k )$, where $k$ is a constant, lies inside circle $C$, (b) show that

$$k ^ { 2 } + 8 k - 5 < 0$$

(c) Hence find the exact set of values of $k$ for which $P$ lies inside $C$.\\

\includegraphics[max width=\textwidth, alt={}, center]{bb1becd5-96c1-426d-9b85-4bbc4a61af27-34_2256_52_315_1978}

\begin{center}

\end{center}

\begin{center}

\end{center}

\hfill \mbox{\textit{Edexcel C12 2017 Q13 [9]}}