Edexcel C12 2019 June — Question 4 6 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2019
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeFind derivative after algebraic simplification (fractional/mixed powers)
DifficultyModerate -0.8 This is a straightforward differentiation question requiring students to rewrite terms as powers of x and apply the power rule. While it has multiple terms and requires algebraic manipulation (converting fractions and roots to index form), it's a standard C1/C2 exercise with no problem-solving or conceptual challenge—purely procedural application of basic differentiation rules.
Spec1.07i Differentiate x^n: for rational n and sums

4. Given that $$y = 5 x ^ { 2 } + \frac { 1 } { 2 x } + \frac { 2 x ^ { 4 } - 8 } { 5 \sqrt { x } } \quad x > 0$$ find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\), giving each term in its simplest form.
(6)
HAVI SIHI NI JINM ION OCVIIV SIHI NI JINAM ION OAVIUV SIHI NI JIIIM ION OC

Question 4:
AnswerMarks Guidance
Working/AnswerMark Guidance
\(\frac{2x^4-8}{5\sqrt{x}} = \frac{2x^4}{5\sqrt{x}} - \frac{8}{5\sqrt{x}} = \frac{2}{5}x^{\frac{7}{2}} - \frac{8}{5}x^{-\frac{1}{2}}\)M1 Attempts to split into two terms where one is of the form \(px^{\frac{7}{2}}\) or \(qx^{-\frac{1}{2}}\); may write as two separate fractions or multiply out \((2x^4-8)\times\frac{1}{5}x^{-\frac{1}{2}}\)
\(\frac{dy}{dx} = \ldots x^1 + \ldots x^{-2} + \ldots x^{\frac{5}{2}} + \ldots x^{-\frac{3}{2}}\)M1 Reduces a correct power by 1 on any term \(x^n \to x^{n-1}\); indices must have been processed
\(\frac{dy}{dx} = 10x - \frac{1}{2}x^{-2} + \frac{7}{5}x^{\frac{5}{2}} + \frac{4}{5}x^{-\frac{3}{2}}\)A1A1A1A1 A1 any one term correct; A1 any two terms correct; A1 any three terms correct; A1 all four terms correct and fully simplified on one line. Accept \(-\frac{1}{2x^2}\), \(+\frac{7\sqrt{x^5}}{5}\), \(+\frac{4}{5x^{\frac{3}{2}}}\), \(0.8x^{-\frac{3}{2}}\) but NOT e.g. \(10x^1\). Beware \(\frac{1}{2x}\to 2x^{-1}\to -2x^{-2}\to -\frac{1}{2x^2}\) is M1A0
## Question 4:

| Working/Answer | Mark | Guidance |
|---|---|---|
| $\frac{2x^4-8}{5\sqrt{x}} = \frac{2x^4}{5\sqrt{x}} - \frac{8}{5\sqrt{x}} = \frac{2}{5}x^{\frac{7}{2}} - \frac{8}{5}x^{-\frac{1}{2}}$ | M1 | Attempts to split into two terms where one is of the form $px^{\frac{7}{2}}$ or $qx^{-\frac{1}{2}}$; may write as two separate fractions or multiply out $(2x^4-8)\times\frac{1}{5}x^{-\frac{1}{2}}$ |
| $\frac{dy}{dx} = \ldots x^1 + \ldots x^{-2} + \ldots x^{\frac{5}{2}} + \ldots x^{-\frac{3}{2}}$ | M1 | Reduces a correct power by 1 on any term $x^n \to x^{n-1}$; indices must have been processed |
| $\frac{dy}{dx} = 10x - \frac{1}{2}x^{-2} + \frac{7}{5}x^{\frac{5}{2}} + \frac{4}{5}x^{-\frac{3}{2}}$ | A1A1A1A1 | A1 any one term correct; A1 any two terms correct; A1 any three terms correct; A1 all four terms correct and fully simplified on one line. Accept $-\frac{1}{2x^2}$, $+\frac{7\sqrt{x^5}}{5}$, $+\frac{4}{5x^{\frac{3}{2}}}$, $0.8x^{-\frac{3}{2}}$ but NOT e.g. $10x^1$. Beware $\frac{1}{2x}\to 2x^{-1}\to -2x^{-2}\to -\frac{1}{2x^2}$ is M1A0 |

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4. Given that

$$y = 5 x ^ { 2 } + \frac { 1 } { 2 x } + \frac { 2 x ^ { 4 } - 8 } { 5 \sqrt { x } } \quad x > 0$$

find $\frac { \mathrm { d } y } { \mathrm {~d} x }$, giving each term in its simplest form.\\
(6)

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HAVI SIHI NI JINM ION OC & VIIV SIHI NI JINAM ION OA & VIUV SIHI NI JIIIM ION OC \\
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\hfill \mbox{\textit{Edexcel C12 2019 Q4 [6]}}