Edexcel C12 2015 June — Question 5 6 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
TypeLogarithmic equation solving
DifficultyModerate -0.8 Part (i) is a direct application of logarithms to solve an exponential equation (take log of both sides), requiring only calculator work. Part (ii) uses the log subtraction rule then solving a linear equation after exponentiating—both are standard textbook exercises with no problem-solving insight needed. This is easier than average A-level content.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

  1. (i) Find, giving your answer to 3 significant figures, the value of \(y\) for which
$$3 ^ { y } = 12$$ (ii) Solve, giving an exact answer, the equation $$\log _ { 2 } ( x + 3 ) - \log _ { 2 } ( 2 x + 4 ) = 4$$ (You should show each step in your working.)

Question 5:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use or state \(y\log 3 = \log 12\) or \(\log_3 12\)M1 Uses power law for logs; may be implied; trial and error valid if \(3^{2.26}=11.9\ldots\) and \(3^{2.27}=12.1\ldots\) shown
\(y = 2.26\) or awrt \(2.26\)A1 Just the answer with no incorrect working scores 2 marks
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use or state \(\log_2 16 = 4\) or \(2^4 = 16\)B1 Connects 16 with '4' correctly; can be scored at any time
\(\log_2(x+3) - \log_2(2x+4) = \log_2\frac{(x+3)}{(2x+4)}\)M1 Correct use of addition or subtraction law of logs
\(\frac{x+3}{(2x+4)} = 16\)A1 Correct equation not involving logs
\(x = -\dfrac{61}{31}\)A1 cso
## Question 5:

### Part (i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Use or state $y\log 3 = \log 12$ or $\log_3 12$ | M1 | Uses power law for logs; may be implied; trial and error valid if $3^{2.26}=11.9\ldots$ **and** $3^{2.27}=12.1\ldots$ shown |
| $y = 2.26$ or awrt $2.26$ | A1 | Just the answer with no incorrect working scores 2 marks |

### Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Use or state $\log_2 16 = 4$ or $2^4 = 16$ | B1 | Connects 16 with '4' correctly; can be scored at any time |
| $\log_2(x+3) - \log_2(2x+4) = \log_2\frac{(x+3)}{(2x+4)}$ | M1 | Correct use of addition or subtraction law of logs |
| $\frac{x+3}{(2x+4)} = 16$ | A1 | Correct equation not involving logs |
| $x = -\dfrac{61}{31}$ | A1 | cso |

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\begin{enumerate}
  \item (i) Find, giving your answer to 3 significant figures, the value of $y$ for which
\end{enumerate}

$$3 ^ { y } = 12$$

(ii) Solve, giving an exact answer, the equation

$$\log _ { 2 } ( x + 3 ) - \log _ { 2 } ( 2 x + 4 ) = 4$$

(You should show each step in your working.)\\

\hfill \mbox{\textit{Edexcel C12 2015 Q5 [6]}}