Edexcel C12 2017 January — Question 1 7 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2017
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeFind range where function increasing/decreasing
DifficultyModerate -0.8 This is a straightforward C1/C2 question requiring basic polynomial differentiation using the power rule, then solving a quadratic inequality. Both parts are standard textbook exercises with no problem-solving insight needed, making it easier than average but not trivial since part (b) requires factorizing and determining inequality regions.
Spec1.02g Inequalities: linear and quadratic in single variable1.07i Differentiate x^n: for rational n and sums

Given \(y = \frac { x ^ { 3 } } { 3 } - 2 x ^ { 2 } + 3 x + 5\)
  1. find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\), simplifying each term.
  2. Hence find the set of values of \(x\) for which \(\frac { \mathrm { d } y } { \mathrm {~d} x } > 0\)

Question 1:
Part (a)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(x^n \rightarrow x^{n-1}\) or \(5 \rightarrow 0\)M1 Method mark for differentiation
\(\frac{dy}{dx} = \frac{3x^2}{3} - 2 \times 2x + 3\)M1A1 Any 3 of the 4 terms differentiated correctly; could be 2 terms correct and \(5 \rightarrow 0\); allow simplified or unsimplified including \(3x^0\) for 3
\(\frac{dy}{dx} = x^2 - 4x + 3\)A1 All 3 terms correct, simplified, on same line, no \(+0\). Do not allow \(1x^2\) for \(x^2\), \(x^1\) for \(x\), or \(3x^0\) for \(3\). Condone omission of \(dy/dx =\) or use of \(y=\)
Note: Candidates who multiply by 3 before differentiating e.g. \(\left(\frac{x^3}{3} - 2x^2 + 3x + 5\right) \times 3 = x^3 - 6x^2 + 9x + 15 \Rightarrow \frac{dy}{dx} = 3x^2 - 12x + 9\) score M1A0A0 but could recover in (a) if they divide by 3. If they persist with \(\frac{dy}{dx} = 3x^2 - 12x + 9\) in (b), allow full recovery in (b).
Part (b)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(x^2 - 4x + 3 = 0 \Rightarrow x = 1, \ 3\)M1A1 M1: Attempt to solve their 3TQ from part (a) as far as \(x = \ldots\); if no working shown and roots incorrect for their 3TQ, score M0; A1: Correct values (may be implied by inequalities)
\(x <\) "1", \(x >\) "3"M1 Chooses outside region (\(x <\) their lower limit, \(x >\) their upper limit). Do not award simply for diagram or table.
\(x < 1, \ x > 3\)A1 Correct answer. Allow regions separated by comma or written separately e.g. \((-\infty, 1) \cup (3, \infty)\). Do not allow \(1 > x > 3\) or \(x < 1\) and \(x > 3\). Answers using \(\leq, \geq\) lose final mark as would \([-\infty,1] \cup [3,\infty]\)
## Question 1:

### Part (a)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $x^n \rightarrow x^{n-1}$ or $5 \rightarrow 0$ | M1 | Method mark for differentiation |
| $\frac{dy}{dx} = \frac{3x^2}{3} - 2 \times 2x + 3$ | M1A1 | Any 3 of the 4 terms differentiated correctly; could be 2 terms correct and $5 \rightarrow 0$; allow simplified or unsimplified including $3x^0$ for 3 |
| $\frac{dy}{dx} = x^2 - 4x + 3$ | A1 | All 3 terms correct, simplified, on same line, no $+0$. Do not allow $1x^2$ for $x^2$, $x^1$ for $x$, or $3x^0$ for $3$. Condone omission of $dy/dx =$ or use of $y=$ |

**Note:** Candidates who multiply by 3 before differentiating e.g. $\left(\frac{x^3}{3} - 2x^2 + 3x + 5\right) \times 3 = x^3 - 6x^2 + 9x + 15 \Rightarrow \frac{dy}{dx} = 3x^2 - 12x + 9$ score M1A0A0 but could recover in (a) if they divide by 3. If they persist with $\frac{dy}{dx} = 3x^2 - 12x + 9$ in (b), allow full recovery in (b).

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### Part (b)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $x^2 - 4x + 3 = 0 \Rightarrow x = 1, \ 3$ | M1A1 | M1: Attempt to solve their 3TQ from part (a) as far as $x = \ldots$; if no working shown and roots incorrect for their 3TQ, score M0; A1: Correct values (may be implied by inequalities) |
| $x <$ "1", $x >$ "3" | M1 | Chooses outside region ($x <$ their lower limit, $x >$ their upper limit). Do not award simply for diagram or table. |
| $x < 1, \ x > 3$ | A1 | Correct answer. Allow regions separated by comma or written separately e.g. $(-\infty, 1) \cup (3, \infty)$. Do not allow $1 > x > 3$ or $x < 1$ **and** $x > 3$. Answers using $\leq, \geq$ lose final mark as would $[-\infty,1] \cup [3,\infty]$ |

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Given $y = \frac { x ^ { 3 } } { 3 } - 2 x ^ { 2 } + 3 x + 5$
\begin{enumerate}[label=(\alph*)]
\item find $\frac { \mathrm { d } y } { \mathrm {~d} x }$, simplifying each term.
\item Hence find the set of values of $x$ for which $\frac { \mathrm { d } y } { \mathrm {~d} x } > 0$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2017 Q1 [7]}}