| Exam Board | Edexcel |
|---|---|
| Module | C12 (Core Mathematics 1 & 2) |
| Year | 2017 |
| Session | January |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Stationary points and optimisation |
| Type | Find range where function increasing/decreasing |
| Difficulty | Moderate -0.8 This is a straightforward C1/C2 question requiring basic polynomial differentiation using the power rule, then solving a quadratic inequality. Both parts are standard textbook exercises with no problem-solving insight needed, making it easier than average but not trivial since part (b) requires factorizing and determining inequality regions. |
| Spec | 1.02g Inequalities: linear and quadratic in single variable1.07i Differentiate x^n: for rational n and sums |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(x^n \rightarrow x^{n-1}\) or \(5 \rightarrow 0\) | M1 | Method mark for differentiation |
| \(\frac{dy}{dx} = \frac{3x^2}{3} - 2 \times 2x + 3\) | M1A1 | Any 3 of the 4 terms differentiated correctly; could be 2 terms correct and \(5 \rightarrow 0\); allow simplified or unsimplified including \(3x^0\) for 3 |
| \(\frac{dy}{dx} = x^2 - 4x + 3\) | A1 | All 3 terms correct, simplified, on same line, no \(+0\). Do not allow \(1x^2\) for \(x^2\), \(x^1\) for \(x\), or \(3x^0\) for \(3\). Condone omission of \(dy/dx =\) or use of \(y=\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(x^2 - 4x + 3 = 0 \Rightarrow x = 1, \ 3\) | M1A1 | M1: Attempt to solve their 3TQ from part (a) as far as \(x = \ldots\); if no working shown and roots incorrect for their 3TQ, score M0; A1: Correct values (may be implied by inequalities) |
| \(x <\) "1", \(x >\) "3" | M1 | Chooses outside region (\(x <\) their lower limit, \(x >\) their upper limit). Do not award simply for diagram or table. |
| \(x < 1, \ x > 3\) | A1 | Correct answer. Allow regions separated by comma or written separately e.g. \((-\infty, 1) \cup (3, \infty)\). Do not allow \(1 > x > 3\) or \(x < 1\) and \(x > 3\). Answers using \(\leq, \geq\) lose final mark as would \([-\infty,1] \cup [3,\infty]\) |
## Question 1:
### Part (a)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $x^n \rightarrow x^{n-1}$ or $5 \rightarrow 0$ | M1 | Method mark for differentiation |
| $\frac{dy}{dx} = \frac{3x^2}{3} - 2 \times 2x + 3$ | M1A1 | Any 3 of the 4 terms differentiated correctly; could be 2 terms correct and $5 \rightarrow 0$; allow simplified or unsimplified including $3x^0$ for 3 |
| $\frac{dy}{dx} = x^2 - 4x + 3$ | A1 | All 3 terms correct, simplified, on same line, no $+0$. Do not allow $1x^2$ for $x^2$, $x^1$ for $x$, or $3x^0$ for $3$. Condone omission of $dy/dx =$ or use of $y=$ |
**Note:** Candidates who multiply by 3 before differentiating e.g. $\left(\frac{x^3}{3} - 2x^2 + 3x + 5\right) \times 3 = x^3 - 6x^2 + 9x + 15 \Rightarrow \frac{dy}{dx} = 3x^2 - 12x + 9$ score M1A0A0 but could recover in (a) if they divide by 3. If they persist with $\frac{dy}{dx} = 3x^2 - 12x + 9$ in (b), allow full recovery in (b).
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### Part (b)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $x^2 - 4x + 3 = 0 \Rightarrow x = 1, \ 3$ | M1A1 | M1: Attempt to solve their 3TQ from part (a) as far as $x = \ldots$; if no working shown and roots incorrect for their 3TQ, score M0; A1: Correct values (may be implied by inequalities) |
| $x <$ "1", $x >$ "3" | M1 | Chooses outside region ($x <$ their lower limit, $x >$ their upper limit). Do not award simply for diagram or table. |
| $x < 1, \ x > 3$ | A1 | Correct answer. Allow regions separated by comma or written separately e.g. $(-\infty, 1) \cup (3, \infty)$. Do not allow $1 > x > 3$ or $x < 1$ **and** $x > 3$. Answers using $\leq, \geq$ lose final mark as would $[-\infty,1] \cup [3,\infty]$ |
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Given $y = \frac { x ^ { 3 } } { 3 } - 2 x ^ { 2 } + 3 x + 5$
\begin{enumerate}[label=(\alph*)]
\item find $\frac { \mathrm { d } y } { \mathrm {~d} x }$, simplifying each term.
\item Hence find the set of values of $x$ for which $\frac { \mathrm { d } y } { \mathrm {~d} x } > 0$
\end{enumerate}
\hfill \mbox{\textit{Edexcel C12 2017 Q1 [7]}}