Edexcel C12 2017 January — Question 13 11 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2017
SessionJanuary
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypePolynomial intersection with algebra
DifficultyStandard +0.3 This is a straightforward multi-part question requiring standard curve sketching techniques (finding intercepts), equating two functions algebraically, and solving a cubic equation with a given root. All steps are routine C1/C2 techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.02n Sketch curves: simple equations including polynomials1.02q Use intersection points: of graphs to solve equations

13. (a) On separate axes sketch the graphs of
  1. \(y = c ^ { 2 } - x ^ { 2 }\)
  2. \(y = x ^ { 2 } ( x - 3 c )\) where \(c\) is a positive constant.
    Show clearly the coordinates of the points where each graph crosses or meets the \(x\)-axis and the \(y\)-axis.
    (b) Prove that the \(x\) coordinate of any point of intersection of $$y = c ^ { 2 } - x ^ { 2 } \text { and } y = x ^ { 2 } ( x - 3 c )$$ where \(c\) is a positive constant, is given by a solution of the equation $$x ^ { 3 } + ( 1 - 3 c ) x ^ { 2 } - c ^ { 2 } = 0$$ Given that the graphs meet when \(x = 2\) (c) find the exact value of \(c\), writing your answer as a fully simplified surd.

Question 13:
Part (a)(i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Sketch showing a curve with maximum on \(y\)-axis, passing through \((-c, 0)\), \((c, 0)\) and \((0, c^2)\)B1 Shape must be smooth at maximum, not pointed. Branches must not turn back on themselves. Allow \((0,-c)\), \((0,c)\) and \((c^2, 0)\) if marked in correct places. Sketch takes precedence over labels.
Fully correct diagram: maximum on \(y\)-axis, branches extend below \(x\)-axis, correct interceptsB1 Intercepts must be correctly labelled and curve in correct position
Part (a)(ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Positive cubic shape with one maximum and one minimumB1 Curve must be smooth at maximum and minimum (not pointed)
Curve touches or meets \(x\)-axis at origin and at \((3c, 0)\) with no other intersectionsB1 Origin need not be marked but \((3c,0)\) must be. Allow \(3c\) or \((0,3c)\) marked in correct place. Sketch takes precedence.
Maximum at the originB1 Allow maximum to form a point or cusp
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(x^2(x-3c) = c^2 - x^2 \Rightarrow x^3 - 3cx^2 = c^2 - x^2\)M1 Sets equations equal and attempts to multiply out bracket or vice versa
\(x^3 + x^2 - 3cx^2 - c^2 = 0\) \(\Rightarrow x^3 + (1-3c)x^2 - c^2 = 0\)*A1* Collects to one side, factorises \(x^2\) terms. Must have intermediate line of working. Allow \(x^3 + x^2(1-3c) - c^2 = 0\) or \(0 = x^3 + (1-3c)x^2 - c^2\)
Part (c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(8 + 4(1-3c) - c^2 = 0\)M1 Substitutes \(x=2\) to give a correct unsimplified form
\(c^2 + 12c - 12 = 0\)A1 Correct 3-term quadratic. Allow equivalent forms (may be implied)
\((c+6)^2 - 36 - 12 = 0 \Rightarrow c = \ldots\) or \(c = \dfrac{-12 \pm \sqrt{12^2 - 4\times1\times(-12)}}{2}\)M1 Solves their 3TQ using formula or completing the square only. Implied by correct exact answer for their 3TQ
\(4\sqrt{3} - 6\)A1 \(c = 4\sqrt{3}-6\) or \(c = -6+4\sqrt{3}\) only
## Question 13:

### Part (a)(i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Sketch showing a curve with maximum on $y$-axis, passing through $(-c, 0)$, $(c, 0)$ and $(0, c^2)$ | B1 | Shape must be smooth at maximum, not pointed. Branches must not turn back on themselves. Allow $(0,-c)$, $(0,c)$ and $(c^2, 0)$ if marked in correct places. Sketch takes precedence over labels. |
| Fully correct diagram: maximum on $y$-axis, branches extend below $x$-axis, correct intercepts | B1 | Intercepts must be correctly labelled and curve in correct position |

### Part (a)(ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Positive cubic shape with one maximum and one minimum | B1 | Curve must be smooth at maximum and minimum (not pointed) |
| Curve touches or meets $x$-axis at origin and at $(3c, 0)$ with no other intersections | B1 | Origin need not be marked but $(3c,0)$ must be. Allow $3c$ or $(0,3c)$ marked in correct place. Sketch takes precedence. |
| Maximum at the origin | B1 | Allow maximum to form a point or cusp |

### Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $x^2(x-3c) = c^2 - x^2 \Rightarrow x^3 - 3cx^2 = c^2 - x^2$ | M1 | Sets equations equal and attempts to multiply out bracket or vice versa |
| $x^3 + x^2 - 3cx^2 - c^2 = 0$ $\Rightarrow x^3 + (1-3c)x^2 - c^2 = 0$* | A1* | Collects to one side, factorises $x^2$ terms. **Must have intermediate line of working.** Allow $x^3 + x^2(1-3c) - c^2 = 0$ or $0 = x^3 + (1-3c)x^2 - c^2$ |

### Part (c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $8 + 4(1-3c) - c^2 = 0$ | M1 | Substitutes $x=2$ to give a **correct** unsimplified form |
| $c^2 + 12c - 12 = 0$ | A1 | Correct 3-term quadratic. Allow equivalent forms (may be implied) |
| $(c+6)^2 - 36 - 12 = 0 \Rightarrow c = \ldots$ or $c = \dfrac{-12 \pm \sqrt{12^2 - 4\times1\times(-12)}}{2}$ | M1 | Solves their 3TQ using formula or completing the square **only**. Implied by correct exact answer for their 3TQ |
| $4\sqrt{3} - 6$ | A1 | $c = 4\sqrt{3}-6$ or $c = -6+4\sqrt{3}$ **only** |

---
13. (a) On separate axes sketch the graphs of
\begin{enumerate}[label=(\roman*)]
\item $y = c ^ { 2 } - x ^ { 2 }$
\item $y = x ^ { 2 } ( x - 3 c )$\\
where $c$ is a positive constant.\\
Show clearly the coordinates of the points where each graph crosses or meets the $x$-axis and the $y$-axis.\\
(b) Prove that the $x$ coordinate of any point of intersection of

$$y = c ^ { 2 } - x ^ { 2 } \text { and } y = x ^ { 2 } ( x - 3 c )$$

where $c$ is a positive constant, is given by a solution of the equation

$$x ^ { 3 } + ( 1 - 3 c ) x ^ { 2 } - c ^ { 2 } = 0$$

Given that the graphs meet when $x = 2$\\
(c) find the exact value of $c$, writing your answer as a fully simplified surd.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2017 Q13 [11]}}