Edexcel P1 2019 October — Question 2 5 marks

Exam BoardEdexcel
ModuleP1 (Pure Mathematics 1)
Year2019
SessionOctober
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimultaneous equations
TypeLinear function from conditions
DifficultyEasy -1.3 This is a straightforward application of forming and solving two simultaneous linear equations from given conditions. Students substitute t=2 and t=7 into H=at+b, then solve the resulting system using basic algebraic manipulation. Part (b) requires only recognizing that t=0 gives the initial height. This is simpler than average A-level content, requiring only routine algebraic skills with no problem-solving insight.
Spec1.02c Simultaneous equations: two variables by elimination and substitution1.02z Models in context: use functions in modelling

2. A tree was planted in the ground. Exactly 2 years after it was planted, the height of the tree was 1.85 m . Exactly 7 years after it was planted, the height of the tree was 3.45 m . Given that the height, \(H\) metres, of the tree, \(t\) years after it was planted in the ground, can be modelled by the equation $$H = a t + b$$ where \(a\) and \(b\) are constants,
  1. find the value of \(a\) and the value of \(b\).
  2. State, according to the model, the height of the tree when it was planted.

Question 2:
Part (a)
AnswerMarks Guidance
WorkingMark Guidance
\(1.85 = 2a + b\)M1 For either equation
\(1.85 = 2a+b\) and \(3.45 = 7a+b\)A1 For both equations correct
Solves simultaneously to get \(a = 0.32, b = 1.21\) (oe)dM1 Solves simultaneously to get a value for \(a\) and \(b\)
\(a = 0.32, b = 1.21\)A1 Or equivalent fractions. May be seen in the equation
Part (b)
AnswerMarks Guidance
WorkingMark Guidance
States 1.21 m or 121 cm (oe)B1ft Correct answer or follow through on their positive \(b\). Accept oe including units
# Question 2:

## Part (a)
| Working | Mark | Guidance |
|---------|------|----------|
| $1.85 = 2a + b$ | M1 | For either equation |
| $1.85 = 2a+b$ and $3.45 = 7a+b$ | A1 | For both equations correct |
| Solves simultaneously to get $a = 0.32, b = 1.21$ (oe) | dM1 | Solves simultaneously to get a value for $a$ and $b$ |
| $a = 0.32, b = 1.21$ | A1 | Or equivalent fractions. May be seen in the equation |

## Part (b)
| Working | Mark | Guidance |
|---------|------|----------|
| States 1.21 m or 121 cm (oe) | B1ft | Correct answer or follow through on their positive $b$. Accept oe including units |

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2. A tree was planted in the ground.

Exactly 2 years after it was planted, the height of the tree was 1.85 m .

Exactly 7 years after it was planted, the height of the tree was 3.45 m .

Given that the height, $H$ metres, of the tree, $t$ years after it was planted in the ground, can be modelled by the equation

$$H = a t + b$$

where $a$ and $b$ are constants,
\begin{enumerate}[label=(\alph*)]
\item find the value of $a$ and the value of $b$.
\item State, according to the model, the height of the tree when it was planted.\\

\begin{center}

\end{center}
\end{enumerate}

\hfill \mbox{\textit{Edexcel P1 2019 Q2 [5]}}