Edexcel P1 2021 June — Question 2

Exam BoardEdexcel
ModuleP1 (Pure Mathematics 1)
Year2021
SessionJune
TopicFactor & Remainder Theorem
TypeSolve p(algebraic transform) = 0

2. In this question you must show all stages of your working. Solutions relying on calculator technology are not acceptable. $$f ( x ) = a x ^ { 3 } + ( 6 a + 8 ) x ^ { 2 } - a ^ { 2 } x$$ where \(a\) is a positive constant. Given \(\mathrm { f } ( - 1 ) = 32\)
    1. show that the only possible value for \(a\) is 3
    2. Using \(a = 3\) solve the equation $$\mathrm { f } ( x ) = 0$$
  1. Hence find all real solutions of
    1. \(3 y + 26 y ^ { \frac { 2 } { 3 } } - 9 y ^ { \frac { 1 } { 3 } } = 0\)
    2. \(3 \left( 9 ^ { 3 z } \right) + 26 \left( 9 ^ { 2 z } \right) - 9 \left( 9 ^ { z } \right) = 0\)