CAIE S2 2016 November — Question 4 5 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2016
SessionNovember
Marks5
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TopicType I/II errors and power of test
TypeFind sample size from partial test information
DifficultyChallenging +1.2 This question requires understanding of critical regions for hypothesis tests and working backwards from a z-value to find constraints on sample size. While it involves multiple steps (identifying the test type, using the critical value z=1.645 for 5% one-tailed test, setting up inequality 1.645×1.6/√n ≤ 0.4, solving for n ≥ 43.3), these are all standard procedures for S2 level. The 'working backwards' aspect adds modest problem-solving demand beyond routine hypothesis test questions, but the mathematical techniques required are straightforward.
Spec2.05a Hypothesis testing language: null, alternative, p-value, significance5.05c Hypothesis test: normal distribution for population mean

4 The manufacturer of a tablet computer claims that the mean battery life is 11 hours. A consumer organisation wished to test whether the mean is actually greater than 11 hours. They invited a random sample of members to report the battery life of their tablets. They then calculated the sample mean. Unfortunately a fire destroyed the records of this test except for the following partial document. \includegraphics[max width=\textwidth, alt={}, center]{c460afa4-1387-421d-87ac-74a64be99714-2_467_593_1612_776} Given that the population of battery lives is normally distributed with standard deviation 1.6 hours, find the set of possible values of the sample size, \(n\).

Question 4:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{11.8 - 11}{1.6 \div \sqrt{n}} = 1.645\)M1 M1 for \(\frac{11.8-11}{1.6\div\sqrt{n}}=\) any \(z\); allow var/sd mix for 1.6 but need \(\sqrt{n}\)
\(\frac{11.8 - 11}{1.6 \div \sqrt{n}} = 1.96\)
\(n = 10.8\) (allow 11)B1 B1 for each correct \(z\)
\(n = 15.4\) (allow 15)B1
A1for both
Possible values are 11, 12, 13, 14, 15A1 [5]
## Question 4:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{11.8 - 11}{1.6 \div \sqrt{n}} = 1.645$ | M1 | M1 for $\frac{11.8-11}{1.6\div\sqrt{n}}=$ any $z$; allow var/sd mix for 1.6 but need $\sqrt{n}$ |
| $\frac{11.8 - 11}{1.6 \div \sqrt{n}} = 1.96$ | | |
| $n = 10.8$ (allow 11) | B1 | B1 for each correct $z$ |
| $n = 15.4$ (allow 15) | B1 | |
| | A1 | for both |
| Possible values are 11, 12, 13, 14, 15 | A1 | [5] | not for just $11 \leqslant n \leqslant 15$ oe |

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4 The manufacturer of a tablet computer claims that the mean battery life is 11 hours. A consumer organisation wished to test whether the mean is actually greater than 11 hours. They invited a random sample of members to report the battery life of their tablets. They then calculated the sample mean. Unfortunately a fire destroyed the records of this test except for the following partial document.\\
\includegraphics[max width=\textwidth, alt={}, center]{c460afa4-1387-421d-87ac-74a64be99714-2_467_593_1612_776}

Given that the population of battery lives is normally distributed with standard deviation 1.6 hours, find the set of possible values of the sample size, $n$.

\hfill \mbox{\textit{CAIE S2 2016 Q4 [5]}}