CAIE S2 2017 March — Question 3 5 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2017
SessionMarch
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentral limit theorem
TypeJustifying CLT for sampling distribution
DifficultyModerate -0.8 Part (i) is a standard CLT application requiring only the formula for sampling distribution (mean μ, SD σ/√n) and normal probability calculation. Part (ii) tests understanding that CLT is needed because the population distribution of X is not stated to be normal—this is routine conceptual recall rather than problem-solving. The question is straightforward with no novel insight required, making it easier than average.
Spec2.04e Normal distribution: as model N(mu, sigma^2)5.05a Sample mean distribution: central limit theorem

3 The length, in centimetres, of a certain type of snake is modelled by the random variable \(X\) with mean 52 and standard deviation 6.1. A random sample of 75 snakes is selected, and the sample mean, \(\bar { X }\), is found.
  1. Find \(\mathrm { P } ( 51 < \bar { X } < 53 )\).
  2. Explain why it was necessary to use the Central Limit theorem in the solution to part (i).

Question 3(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{53-52}{6.1\div\sqrt{75}}\) \((= 1.420)\)M1
\(\frac{51-52}{6.1\div\sqrt{75}}\) \((= -1.420)\)M1 or \(-\)"\(1.420\)" seen
\(\Phi(\text{"1.420"}) - \Phi(\text{"-1.420"})\)M1
\(= 0.844\) (3 sfs)A1
Question 3(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Need to assume \(\bar{X}\) (approx.) normally distributedB1 or \(X\) not stated to be normally distributed
## Question 3(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{53-52}{6.1\div\sqrt{75}}$ $(= 1.420)$ | M1 | |
| $\frac{51-52}{6.1\div\sqrt{75}}$ $(= -1.420)$ | M1 | or $-$"$1.420$" seen |
| $\Phi(\text{"1.420"}) - \Phi(\text{"-1.420"})$ | M1 | |
| $= 0.844$ (3 sfs) | A1 | |

## Question 3(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Need to assume $\bar{X}$ (approx.) normally distributed | B1 | or $X$ not stated to be normally distributed |

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3 The length, in centimetres, of a certain type of snake is modelled by the random variable $X$ with mean 52 and standard deviation 6.1. A random sample of 75 snakes is selected, and the sample mean, $\bar { X }$, is found.\\
(i) Find $\mathrm { P } ( 51 < \bar { X } < 53 )$.\\

(ii) Explain why it was necessary to use the Central Limit theorem in the solution to part (i).\\

\hfill \mbox{\textit{CAIE S2 2017 Q3 [5]}}