CAIE S2 2021 November — Question 7 9 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2021
SessionNovember
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Probability Distributions and Random Variables
TypeSingle-piece PDF with k
DifficultyStandard +0.3 This is a straightforward S2 question testing standard pdf techniques: part (a)(i) uses integration to find k (routine calculus), part (a)(ii) finds E(X) using the standard formula, and part (b) applies symmetry properties of pdfs with basic probability manipulation. All steps are textbook exercises requiring recall and direct application rather than problem-solving or insight.
Spec5.03a Continuous random variables: pdf and cdf5.03b Solve problems: using pdf5.03c Calculate mean/variance: by integration

7
  1. The probability density function of the random variable \(X\) is given by $$f ( x ) = \begin{cases} k x ( 4 - x ) & 0 \leqslant x \leqslant 2 \\ 0 & \text { otherwise } \end{cases}$$ where \(k\) is a constant.
    1. Show that \(k = \frac { 3 } { 16 }\).
    2. Find \(\mathrm { E } ( X )\).
  2. The random variable \(Y\) has the following properties.
    Given that \(\mathrm { P } ( Y < a ) = 0.2\), find \(\mathrm { P } ( 2.5 < Y < 5 - a )\) illustrating your method with a sketch on the axes provided. \includegraphics[max width=\textwidth, alt={}, center]{cea87af9-4b2a-4297-91e9-4eb5744b9e48-11_369_837_621_694}
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 7(a)(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(k\displaystyle\int_0^{2}(4x - x^2)\,dx = 1\)M1 Attempt integral \(f(x)\) and \(= 1\). Ignore limits (must see a power increase for attempted integration)
\(k\!\left[\dfrac{4x^2}{2} - \dfrac{x^3}{3}\right]_0^2 = 1\)A1 Correct integration and correct limits
\(k \times \dfrac{16}{3} = 1\ \left[k = \dfrac{3}{16}\right]\)A1 OE AG. Convincingly obtained. At least one interim step. No errors seen
3
Question 7(a)(ii):
AnswerMarks Guidance
AnswerMark Guidance
\(\frac{3}{16}\int_{0}^{2}(4x^2 - x^3)\,dx\)M1 Attempt integral \(xf(x)\). Ignore limits. (must see a power increase for attempted integration). Condone missing \(k\).
\(\frac{3}{16}\left[\frac{4x^2}{2} - \frac{x^3}{3}\right]_{0}^{2}\)A1 Correct integration and correct limits. Condone missing \(k\).
\(\frac{5}{4}\)A1 Unsupported correct answer scores SC B2 only.
3
Question 7(b):
AnswerMarks Guidance
AnswerMark Guidance
Symmetrical frequency density graph, 0 to 5, showing area 0.2 to left of \(a\)B1 With \(a\) to the left of centre.
Either 0.2 between \(5-a\) and 5 or 0.8 between 0 and \(5-a\)B1 Shown on graph or stated (\(5-a\) seen or implied). \(a\) must be non-numerical.
\([P(2.5 < Y < 5-a)] = 0.3\)B1 Must be clearly final answer. \(a\) must be non-numerical.
3
## Question 7(a)(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $k\displaystyle\int_0^{2}(4x - x^2)\,dx = 1$ | **M1** | Attempt integral $f(x)$ and $= 1$. Ignore limits (must see a power increase for attempted integration) |
| $k\!\left[\dfrac{4x^2}{2} - \dfrac{x^3}{3}\right]_0^2 = 1$ | **A1** | Correct integration and correct limits |
| $k \times \dfrac{16}{3} = 1\ \left[k = \dfrac{3}{16}\right]$ | **A1** | OE AG. Convincingly obtained. At least one interim step. No errors seen |
| | **3** | |

## Question 7(a)(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| $\frac{3}{16}\int_{0}^{2}(4x^2 - x^3)\,dx$ | **M1** | Attempt integral $xf(x)$. Ignore limits. (must see a power increase for attempted integration). Condone missing $k$. |
| $\frac{3}{16}\left[\frac{4x^2}{2} - \frac{x^3}{3}\right]_{0}^{2}$ | **A1** | Correct integration and correct limits. Condone missing $k$. |
| $\frac{5}{4}$ | **A1** | Unsupported correct answer scores **SC B2** only. |
| | **3** | |

---

## Question 7(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Symmetrical frequency density graph, 0 to 5, showing area 0.2 to left of $a$ | **B1** | With $a$ to the left of centre. |
| Either 0.2 between $5-a$ and 5 or 0.8 between 0 and $5-a$ | **B1** | Shown on graph or stated ($5-a$ seen or implied). $a$ must be non-numerical. |
| $[P(2.5 < Y < 5-a)] = 0.3$ | **B1** | Must be clearly final answer. $a$ must be non-numerical. |
| | **3** | |
7
\begin{enumerate}[label=(\alph*)]
\item The probability density function of the random variable $X$ is given by

$$f ( x ) = \begin{cases} k x ( 4 - x ) & 0 \leqslant x \leqslant 2 \\ 0 & \text { otherwise } \end{cases}$$

where $k$ is a constant.
\begin{enumerate}[label=(\roman*)]
\item Show that $k = \frac { 3 } { 16 }$.
\item Find $\mathrm { E } ( X )$.
\end{enumerate}\item The random variable $Y$ has the following properties.

\begin{itemize}
  \item $Y$ takes values between 0 and 5 only.
  \item The probability density function of $Y$ is symmetrical.
\end{itemize}

Given that $\mathrm { P } ( Y < a ) = 0.2$, find $\mathrm { P } ( 2.5 < Y < 5 - a )$ illustrating your method with a sketch on the axes provided.\\
\includegraphics[max width=\textwidth, alt={}, center]{cea87af9-4b2a-4297-91e9-4eb5744b9e48-11_369_837_621_694}\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE S2 2021 Q7 [9]}}