CAIE P1 2019 June — Question 1 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2019
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeSingle coefficient given directly
DifficultyModerate -0.8 This is a straightforward binomial expansion question requiring identification of the constant term using the general term formula, solving a simple equation for k, then finding another coefficient. It's routine application of a standard technique with no conceptual challenges, making it easier than average but not trivial since it requires correct setup of the general term.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

1 The term independent of \(x\) in the expansion of \(\left( 2 x + \frac { k } { x } \right) ^ { 6 }\), where \(k\) is a constant, is 540.
  1. Find the value of \(k\).
  2. For this value of \(k\), find the coefficient of \(x ^ { 2 }\) in the expansion.

Question 1:
Part (i):
AnswerMarks Guidance
AnswerMarks Guidance
Independent term \(= (2x)^3 \times \left(\frac{k}{x}\right)^3 \times {}_6C_3\)B2,1,0 Term must be isolated
\(= 540 \rightarrow k = 1\frac{1}{2}\)B1
Total: 3
Part (ii):
AnswerMarks Guidance
AnswerMarks Guidance
Term in \(x^2\) is \((2x)^4 \times \left(\frac{k}{x}\right)^2 \times {}_6C_2\)B1 All correct – even if \(k\) incorrect
\(15 \times 16 \times k^2 = 540\) (or \(540x^2\))B1 FT for \(240k^2\) or \(240k^2x^2\)
Total: 2
## Question 1:

### Part (i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Independent term $= (2x)^3 \times \left(\frac{k}{x}\right)^3 \times {}_6C_3$ | **B2,1,0** | Term must be isolated |
| $= 540 \rightarrow k = 1\frac{1}{2}$ | **B1** | |
| **Total: 3** | | |

### Part (ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Term in $x^2$ is $(2x)^4 \times \left(\frac{k}{x}\right)^2 \times {}_6C_2$ | **B1** | All correct – even if $k$ incorrect |
| $15 \times 16 \times k^2 = 540$ (or $540x^2$) | **B1** | **FT** for $240k^2$ or $240k^2x^2$ |
| **Total: 2** | | |
1 The term independent of $x$ in the expansion of $\left( 2 x + \frac { k } { x } \right) ^ { 6 }$, where $k$ is a constant, is 540.\\
(i) Find the value of $k$.\\

(ii) For this value of $k$, find the coefficient of $x ^ { 2 }$ in the expansion.\\

\hfill \mbox{\textit{CAIE P1 2019 Q1 [5]}}