CAIE S2 2020 June — Question 1 3 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2020
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeStandard unbiased estimates calculation
DifficultyEasy -1.2 This is a straightforward application of standard formulas for unbiased estimates of mean (Σx/n) and variance (Σx²/(n-1) - n(x̄)²/(n-1)). It requires only direct substitution into memorized formulas with no problem-solving, conceptual understanding, or multi-step reasoning—purely mechanical calculation that is easier than average A-level questions.
Spec5.05b Unbiased estimates: of population mean and variance

1 A random sample of 100 values of a variable \(X\) is taken. These values are summarised below. $$n = 100 \quad \Sigma x = 1556 \quad \Sigma x ^ { 2 } = 29004$$ Calculate unbiased estimates of the population mean and variance of \(X\).

Question 1:
AnswerMarks Guidance
AnswerMark Guidance
Est \(\mu = 15.56\)B1
Est \(\sigma^2 = \frac{100}{99}\left(\frac{29004}{100} - \text{"15.56"}^2\right)\) or \(= \frac{1}{99}\left(29004 - \frac{1556^2}{100}\right)\)M1
\(48.4105 = 48.4\) (3 sf)A1
Total: 3 marks
## Question 1:

| Answer | Mark | Guidance |
|--------|------|----------|
| Est $\mu = 15.56$ | B1 | |
| Est $\sigma^2 = \frac{100}{99}\left(\frac{29004}{100} - \text{"15.56"}^2\right)$ or $= \frac{1}{99}\left(29004 - \frac{1556^2}{100}\right)$ | M1 | |
| $48.4105 = 48.4$ (3 sf) | A1 | |

**Total: 3 marks**

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1 A random sample of 100 values of a variable $X$ is taken. These values are summarised below.

$$n = 100 \quad \Sigma x = 1556 \quad \Sigma x ^ { 2 } = 29004$$

Calculate unbiased estimates of the population mean and variance of $X$.\\

\hfill \mbox{\textit{CAIE S2 2020 Q1 [3]}}