CAIE M2 Specimen — Question 2 5 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
SessionSpecimen
Marks5
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TopicCircular Motion 2
TypeConical pendulum (horizontal circle)
DifficultyModerate -0.8 This is a standard conical pendulum problem requiring straightforward application of circular motion principles. Part (i) involves resolving forces vertically (T cos θ = mg) with given geometry, while part (ii) uses horizontal resolution (T sin θ = mv²/r). The geometry is provided explicitly (0.5m string, 0.4m vertical drop gives sin θ = 0.6), making this a routine two-step exercise with no problem-solving insight required—easier than average A-level mechanics.
Spec3.03b Newton's first law: equilibrium3.03e Resolve forces: two dimensions6.05c Horizontal circles: conical pendulum, banked tracks

2 One end of a light inextensible string of length 0.5 m is attached to a fixed point \(A\). A particle \(P\) of mass 0.2 kg is attached to the other end of the string. \(P\) moves with constant speed in a horizontal circle with centre \(O\) which is 0.4 m vertically below \(A\).
  1. Show that the tension in the string is 2.5 N .
  2. Find the speed of \(P\).

Question 2(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(T\cos\theta = 0.2g\), \(T \times \frac{0.4}{0.5} = 2\)M1 Weight = vertical comp of tension
\(T = 2.5\) N (AG)A1
Total: 2
Question 2(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(2.5\sin\theta = \frac{0.2v^2}{r}\)M1 Horiz comp of tension and \(\text{accn} = v^2/r\)
\(2.5 \times \frac{0.3}{0.5} = \frac{0.2v^2}{0.3}\)A1
\(v = 1.5 \text{ ms}^{-1}\)A1
Total: 3
## Question 2(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $T\cos\theta = 0.2g$, $T \times \frac{0.4}{0.5} = 2$ | M1 | Weight = vertical comp of tension |
| $T = 2.5$ N (AG) | A1 | |
| **Total: 2** | | |

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## Question 2(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $2.5\sin\theta = \frac{0.2v^2}{r}$ | M1 | Horiz comp of tension and $\text{accn} = v^2/r$ |
| $2.5 \times \frac{0.3}{0.5} = \frac{0.2v^2}{0.3}$ | A1 | |
| $v = 1.5 \text{ ms}^{-1}$ | A1 | |
| **Total: 3** | | |

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2 One end of a light inextensible string of length 0.5 m is attached to a fixed point $A$. A particle $P$ of mass 0.2 kg is attached to the other end of the string. $P$ moves with constant speed in a horizontal circle with centre $O$ which is 0.4 m vertically below $A$.\\
(i) Show that the tension in the string is 2.5 N .\\

(ii) Find the speed of $P$.\\

\hfill \mbox{\textit{CAIE M2  Q2 [5]}}