CAIE M2 2004 November — Question 5 7 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2004
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHooke's law and elastic energy
TypeHorizontal elastic string on rough surface
DifficultyStandard +0.8 This is a multi-step energy problem requiring careful consideration of elastic potential energy, work done against friction, and kinetic energy. Students must identify that the string becomes slack at natural length, apply Hooke's law correctly, and use the work-energy principle with friction over the correct distance. The combination of elastic strings with friction and energy methods is moderately challenging but follows standard M2 techniques.
Spec3.03v Motion on rough surface: including inclined planes6.02i Conservation of energy: mechanical energy principle

5 One end of a light elastic string of natural length 0.4 m and modulus of elasticity 16 N is attached to a fixed point \(O\) of a horizontal table. A particle \(P\) of mass 0.8 kg is attached to the other end of the string. The particle \(P\) is released from rest on the table, at a point which is 0.5 m from \(O\). The coefficient of friction between the particle and the table is 0.2 . By considering work and energy, find the speed of \(P\) at the instant the string becomes slack.

AnswerMarks Guidance
Loss in EPE = \(\frac{16(0.1)^2}{2 \times 0.4}\)B1 (\(= 0.2\))
For using \(F = \mu R\) and \(R = mg\)M1
\(F = 0.2 \times 0.8 \times 10\)A1 (\(=1.6\))
WD against friction = \(1.6 \times 0.1\)B1 ft (\(= 0.16\))
For using KE gained = EPE lost – WD against frictionM1
\(\frac{1}{2}0.8v^2 = 0.2 - 0.16\)A1 ft
Speed is 0.316 ms\(^{-1}\)A1 7 marks
Loss in EPE = $\frac{16(0.1)^2}{2 \times 0.4}$ | B1 | ($= 0.2$)
For using $F = \mu R$ and $R = mg$ | M1 |
$F = 0.2 \times 0.8 \times 10$ | A1 | ($=1.6$)
WD against friction = $1.6 \times 0.1$ | B1 ft | ($= 0.16$)
For using KE gained = EPE lost – WD against friction | M1 |
$\frac{1}{2}0.8v^2 = 0.2 - 0.16$ | A1 ft |
Speed is 0.316 ms$^{-1}$ | A1 | 7 marks

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5 One end of a light elastic string of natural length 0.4 m and modulus of elasticity 16 N is attached to a fixed point $O$ of a horizontal table. A particle $P$ of mass 0.8 kg is attached to the other end of the string. The particle $P$ is released from rest on the table, at a point which is 0.5 m from $O$. The coefficient of friction between the particle and the table is 0.2 . By considering work and energy, find the speed of $P$ at the instant the string becomes slack.

\hfill \mbox{\textit{CAIE M2 2004 Q5 [7]}}