CAIE M2 2004 November — Question 3 6 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2004
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable Force
TypeTime to reach given speed
DifficultyStandard +0.8 This is a variable force mechanics problem requiring Newton's second law to derive a differential equation (part i is routine), then separating variables and integrating a non-trivial rational function with partial fractions (part ii). The integration requires factorizing 7000-v², decomposing into partial fractions, and evaluating definite integrals with logarithms—significantly more demanding than standard constant acceleration problems but still within M2 scope.
Spec6.06a Variable force: dv/dt or v*dv/dx methods

3 A car of mass 1000 kg is moving on a straight horizontal road. The driving force of the car is \(\frac { 28000 } { v } \mathrm {~N}\) and the resistance to motion is \(4 \nu \mathrm {~N}\), where \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) is the speed of the car \(t\) seconds after it passes a fixed point on the road.
  1. Show that \(\frac { \mathrm { d } v } { \mathrm {~d} t } = \frac { 7000 - v ^ { 2 } } { 250 v }\). The car passes points \(A\) and \(B\) with speeds \(10 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and \(40 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) respectively.
  2. Find the time taken for the car to travel from \(A\) to \(B\).

AnswerMarks Guidance
(i) For using Newton's second law and \(a = \frac{dv}{dt}\)M1
Correct working to obtain the given answerA1 2 marks
(ii) For separating the variables and attempting to integrateM1
\(t = -125\ln(7000 - v^2)\) \((+C)\) (aef)A1
For attempting to find \(t(40) - t(10)\) (or equivalent)M1
Time taken is 30.6 sA1 4 marks
**(i)** For using Newton's second law and $a = \frac{dv}{dt}$ | M1 |
Correct working to obtain the given answer | A1 | 2 marks

**(ii)** For separating the variables and attempting to integrate | M1 |
$t = -125\ln(7000 - v^2)$ $(+C)$ (aef) | A1 |
For attempting to find $t(40) - t(10)$ (or equivalent) | M1 |
Time taken is 30.6 s | A1 | 4 marks

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3 A car of mass 1000 kg is moving on a straight horizontal road. The driving force of the car is $\frac { 28000 } { v } \mathrm {~N}$ and the resistance to motion is $4 \nu \mathrm {~N}$, where $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$ is the speed of the car $t$ seconds after it passes a fixed point on the road.\\
(i) Show that $\frac { \mathrm { d } v } { \mathrm {~d} t } = \frac { 7000 - v ^ { 2 } } { 250 v }$.

The car passes points $A$ and $B$ with speeds $10 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and $40 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ respectively.\\
(ii) Find the time taken for the car to travel from $A$ to $B$.

\hfill \mbox{\textit{CAIE M2 2004 Q3 [6]}}