CAIE M2 2015 June — Question 5 7 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2015
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypePrism or block on inclined plane
DifficultyChallenging +1.2 This is a multi-step mechanics problem requiring moments about the pivot point, resolution of forces, and Hooke's law. While it involves several concepts (equilibrium, toppling condition, elastic strings), the approach is methodical: identify the pivot point B, take moments including the tension component, then use Hooke's law. The geometry is clearly specified and the 30° angles simplify calculations. This is more challenging than routine statics problems but follows standard A-level mechanics procedures without requiring novel insight.
Spec6.04e Rigid body equilibrium: coplanar forces

5 \includegraphics[max width=\textwidth, alt={}, center]{a03ad6c1-b4a3-4007-8d3b-ce289a998a55-3_499_721_715_712} A uniform solid cube with edges of length 0.4 m rests in equilibrium on a rough plane inclined at an angle of \(30 ^ { \circ }\) to the horizontal. \(A B C D\) is a cross-section through the centre of mass of the cube, with \(A B\) along a line of greatest slope. \(B\) lies below the level of \(A\). One end of a light elastic string with modulus of elasticity 12 N and natural length 0.4 m is attached to \(C\). The other end of the string is attached to a point below the level of \(B\) on the same line of greatest slope, such that the string makes an angle of \(30 ^ { \circ }\) with the plane (see diagram). The cube is on the point of toppling. Find
  1. the tension in the string,
  2. the weight of the cube.

Question 5:
Part (i):
AnswerMarks Guidance
Working/AnswerMark Guidance
\(CP = 0.8\)B1 P is the point where the string is attached to the plane
\(T = 12 \times (0.8 - 0.4)/0.4\)M1 Uses \(T = \lambda x / l\)
\(T = 12\text{ N}\)A1
Total: 3 marks
Part (ii):
AnswerMarks Guidance
Working/AnswerMark Guidance
Moment of \(T\) at B \(= 0.4 \times 12\cos30\)B1\(\checkmark\) ft for their \(T\) in (i)
\(0.4 \times 12\cos30 = 0.2W\cos30 - 0.2W\sin30\)M1, A1 Moments about B; Or RHS \(= 0.2\sqrt{2}\cos75W\) or \(W(0.2 - 0.2\tan30)\cos30\)
\(W = 56.8\text{ N}\)A1
Total: 4 marks
## Question 5:

### Part (i):

| Working/Answer | Mark | Guidance |
|---|---|---|
| $CP = 0.8$ | B1 | P is the point where the string is attached to the plane |
| $T = 12 \times (0.8 - 0.4)/0.4$ | M1 | Uses $T = \lambda x / l$ |
| $T = 12\text{ N}$ | A1 | |

**Total: 3 marks**

### Part (ii):

| Working/Answer | Mark | Guidance |
|---|---|---|
| Moment of $T$ at B $= 0.4 \times 12\cos30$ | B1$\checkmark$ | ft for their $T$ in (i) |
| $0.4 \times 12\cos30 = 0.2W\cos30 - 0.2W\sin30$ | M1, A1 | Moments about B; Or RHS $= 0.2\sqrt{2}\cos75W$ or $W(0.2 - 0.2\tan30)\cos30$ |
| $W = 56.8\text{ N}$ | A1 | |

**Total: 4 marks**

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5\\
\includegraphics[max width=\textwidth, alt={}, center]{a03ad6c1-b4a3-4007-8d3b-ce289a998a55-3_499_721_715_712}

A uniform solid cube with edges of length 0.4 m rests in equilibrium on a rough plane inclined at an angle of $30 ^ { \circ }$ to the horizontal. $A B C D$ is a cross-section through the centre of mass of the cube, with $A B$ along a line of greatest slope. $B$ lies below the level of $A$. One end of a light elastic string with modulus of elasticity 12 N and natural length 0.4 m is attached to $C$. The other end of the string is attached to a point below the level of $B$ on the same line of greatest slope, such that the string makes an angle of $30 ^ { \circ }$ with the plane (see diagram). The cube is on the point of toppling. Find\\
(i) the tension in the string,\\
(ii) the weight of the cube.

\hfill \mbox{\textit{CAIE M2 2015 Q5 [7]}}