CAIE M2 2011 June — Question 2 6 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2011
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 2
TypeLamina suspended in equilibrium
DifficultyStandard +0.3 This is a standard centre of mass problem using the known formula for a circular quadrant (distance 4r/3π from centre) followed by a straightforward equilibrium calculation with trigonometry. Both parts require routine application of memorized results with minimal problem-solving, making it slightly easier than average.
Spec6.04b Find centre of mass: using symmetry6.04e Rigid body equilibrium: coplanar forces

2 \includegraphics[max width=\textwidth, alt={}, center]{18398d27-15eb-4515-8210-4f0f614d5b28-2_406_483_431_829} \(A O B\) is a uniform lamina in the shape of a quadrant of a circle with centre \(O\) and radius 0.6 m (see diagram).
  1. Calculate the distance of the centre of mass of the lamina from \(A\). The lamina is freely suspended at \(A\) and hangs in equilibrium.
  2. Find the angle between the vertical and the side \(A O\) of the lamina.

Question 2:
Part (i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x = 2 \times 0.6\sin(\pi/4)/(3\pi/4)\ [= 0.36(0)]\)B1 Centre of mass from O
\(d^2 = 0.6^2 + 0.36^2 - 2 \times 0.6 \times 0.36\cos(\pi/4)\)M1
\(d = 0.429\)A1 [3]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\sin\alpha / 0.36 = \sin(\pi/4)/0.429\)M1
\(\alpha = 36.4°\) or \(0.635^c\)A1, A1 [3]
## Question 2:

### Part (i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $x = 2 \times 0.6\sin(\pi/4)/(3\pi/4)\ [= 0.36(0)]$ | B1 | Centre of mass from O |
| $d^2 = 0.6^2 + 0.36^2 - 2 \times 0.6 \times 0.36\cos(\pi/4)$ | M1 | |
| $d = 0.429$ | A1 [3] | |

### Part (ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sin\alpha / 0.36 = \sin(\pi/4)/0.429$ | M1 | |
| $\alpha = 36.4°$ or $0.635^c$ | A1, A1 [3] | |

---
2\\
\includegraphics[max width=\textwidth, alt={}, center]{18398d27-15eb-4515-8210-4f0f614d5b28-2_406_483_431_829}\\
$A O B$ is a uniform lamina in the shape of a quadrant of a circle with centre $O$ and radius 0.6 m (see diagram).\\
(i) Calculate the distance of the centre of mass of the lamina from $A$.

The lamina is freely suspended at $A$ and hangs in equilibrium.\\
(ii) Find the angle between the vertical and the side $A O$ of the lamina.

\hfill \mbox{\textit{CAIE M2 2011 Q2 [6]}}