Lamina suspended in equilibrium

A question is this type if and only if a lamina is freely suspended from a point and hangs in equilibrium, requiring calculation of the angle made with the vertical or horizontal.

9 questions · Standard +0.9

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CAIE M2 2011 June Q2
6 marks Standard +0.3
2 \includegraphics[max width=\textwidth, alt={}, center]{18398d27-15eb-4515-8210-4f0f614d5b28-2_406_483_431_829} \(A O B\) is a uniform lamina in the shape of a quadrant of a circle with centre \(O\) and radius 0.6 m (see diagram).
  1. Calculate the distance of the centre of mass of the lamina from \(A\). The lamina is freely suspended at \(A\) and hangs in equilibrium.
  2. Find the angle between the vertical and the side \(A O\) of the lamina.
CAIE M2 2012 June Q2
6 marks Standard +0.3
2 \includegraphics[max width=\textwidth, alt={}, center]{6d3892e0-8c88-44ec-940f-c526d71a7fc6-2_481_412_440_865} The diagram shows a circular object formed from a uniform semicircular lamina of weight 11 N and a uniform semicircular arc of weight 9 N . The lamina and the arc both have centre \(O\) and radius 0.7 m and are joined at the ends of their common diameter \(A B\).
  1. Show that the distance of the centre of mass of the object from \(O\) is 0.0371 m , correct to 3 significant figures. The object hangs in equilibrium, freely suspended at \(A\).
  2. Find the angle between \(A B\) and the vertical and state whether the lowest point of the object is on the lamina or on the arc.
CAIE M2 2012 June Q6
9 marks Challenging +1.2
6 \includegraphics[max width=\textwidth, alt={}, center]{09971be0-73b6-4c73-8dfd-c89ff877950a-3_451_775_255_685} The diagram shows a uniform lamina \(A B C D E F\), formed from a semicircle with centre \(O\) and radius 1 m by removing a semicircular part with centre \(O\) and radius \(r \mathrm {~m}\).
  1. Show that the distance in metres of the centre of mass of the lamina from \(O\) is $$\frac { 4 \left( 1 + r + r ^ { 2 } \right) } { 3 \pi ( 1 + r ) } .$$ The centre of mass of the lamina lies on the \(\operatorname { arc } A B C\).
  2. Show that \(r = 0.494\), correct to 3 significant figures. The lamina is freely suspended at \(F\) and hangs in equilibrium.
  3. Find the angle between the diameter of the lamina and the vertical.
CAIE M2 2012 June Q6
9 marks Standard +0.8
6 \includegraphics[max width=\textwidth, alt={}, center]{98bbefd8-b3dd-49f1-8591-e939282cb05c-3_341_791_886_678} A uniform lamina \(A B C D E\) consists of a rectangle \(B C D E\) and an isosceles triangle \(A B E\) joined along their common edge \(B E\). For the triangle, \(A B = A E , B E = a \mathrm {~m}\) and the perpendicular height is \(h \mathrm {~m}\). For the rectangle, \(B C = D E = 0.5 \mathrm {~m}\) and \(C D = B E = a \mathrm {~m}\) (see diagram).
  1. Show that the distance in metres of the centre of mass of the lamina from \(B E\) towards \(C D\) is $$\frac { 3 - 4 h ^ { 2 } } { 12 + 12 h }$$ The lamina is freely suspended at \(E\) and hangs in equilibrium.
  2. Given that \(D E\) is horizontal, calculate \(h\).
  3. Given instead that \(h = 0.5\) and \(A E\) is horizontal, calculate \(a\).
CAIE M2 2016 March Q4
7 marks Standard +0.3
4 \includegraphics[max width=\textwidth, alt={}, center]{334b4bdf-6d9c-4208-9032-572eb7c5f9ee-2_549_579_1505_781} A uniform lamina is made by joining a rectangle \(A B C D\), in which \(A B = C D = 0.56 \mathrm {~m}\) and \(B C = A D = 2 \mathrm {~m}\), and a square \(E F G A\) of side 1.2 m . The vertex \(E\) of the square lies on the edge \(A D\) of the rectangle (see diagram). The centre of mass of the lamina is a distance \(h \mathrm {~m}\) from \(B C\) and a distance \(v \mathrm {~m}\) from \(B A G\).
  1. Find the value of \(h\) and show that \(v = h\). The lamina is freely suspended at the point \(B\) and hangs in equilibrium.
  2. State the angle which the edge \(B C\) makes with the horizontal. Instead, the lamina is now freely suspended at the point \(F\) and hangs in equilibrium.
  3. Calculate the angle between \(F G\) and the vertical.
Edexcel M3 2024 January Q5
16 marks Challenging +1.2
  1. (a) Use algebraic integration to show that the centre of mass of a uniform semicircular disc of radius \(r\) and centre \(O\) is at a distance \(\frac { 4 r } { 3 \pi }\) from the diameter through \(O\) [You may assume, without proof, that the area of a circle of radius \(r\) is \(\pi r ^ { 2 }\) ]
A uniform lamina L is in the shape of a semicircle with centre \(B\) and diameter \(A C = 8 a\). The semicircle with diameter \(A B\) is removed from \(L\) and attached to the straight edge \(B C\) to form the template \(T\), shown shaded in Figure 4. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{92131234-bfc1-4e0e-87d4-db9335fbf343-16_419_1273_680_397} \captionsetup{labelformat=empty} \caption{Figure 4}
\end{figure} The distance of the centre of mass of \(T\) from \(A C\) is \(d\).
(b) Show that \(d = \frac { 4 a } { \pi }\) The template \(T\) is freely suspended from \(A\) and hangs in equilibrium with \(A C\) at an angle \(\theta\) to the downward vertical.
(c) Find the exact value of \(\tan \theta\)
OCR MEI M3 2007 January Q4
18 marks Challenging +1.2
4 In this question, \(a\) is a constant with \(a > 1\).
Fig. 4 shows the region bounded by the curve \(y = \frac { 1 } { x ^ { 2 } }\) for \(1 \leqslant x \leqslant a\), the \(x\)-axis, and the lines \(x = 1\) and \(x = a\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{b209dbe7-769c-4301-a2f3-108c27c8cefb-5_447_848_543_612} \captionsetup{labelformat=empty} \caption{Fig. 4}
\end{figure} This region is occupied by a uniform lamina ABCD , where A is \(( 1,1 ) , \mathrm { B }\) is \(( 1,0 ) , \mathrm { C }\) is \(( a , 0 )\) and D is \(\left( a , \frac { 1 } { a ^ { 2 } } \right)\). The centre of mass of this lamina is \(( \bar { x } , \bar { y } )\).
  1. Find \(\bar { x }\) in terms of \(a\), and show that \(\bar { y } = \frac { a ^ { 3 } - 1 } { 6 \left( a ^ { 3 } - a ^ { 2 } \right) }\).
  2. In the case \(a = 2\), the lamina is freely suspended from the point A , and hangs in equilibrium. Find the angle which AB makes with the vertical. The region shown in Fig. 4 is now rotated through \(2 \pi\) radians about the \(x\)-axis to form a uniform solid of revolution.
  3. Find the \(x\)-coordinate of the centre of mass of this solid of revolution, in terms of \(a\), and show that it is less than 1.5.
Edexcel FM2 2019 June Q3
11 marks Challenging +1.2
  1. Numerical (calculator) integration is not acceptable in this question.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{9b995178-a4be-4d5a-95f8-6c2978ff01b3-08_547_550_303_753} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} The shaded region \(O A B\) in Figure 2 is bounded by the \(x\)-axis, the line with equation \(x = 4\) and the curve with equation \(y = \frac { 1 } { 4 } ( x - 2 ) ^ { 3 } + 2\). The point \(A\) has coordinates (4, 4) and the point \(B\) has coordinates \(( 4,0 )\). A uniform lamina \(L\) has the shape of \(O A B\). The unit of length on both axes is one centimetre. The centre of mass of \(L\) is at the point with coordinates \(( \bar { x } , \bar { y } )\). Given that the area of \(L\) is \(8 \mathrm {~cm} ^ { 2 }\),
  1. show that \(\bar { y } = \frac { 8 } { 7 }\) The lamina is freely suspended from \(A\) and hangs in equilibrium with \(A B\) at an angle \(\theta ^ { \circ }\) to the downward vertical.
  2. Find the value of \(\theta\).
OCR Further Mechanics 2022 June Q5
9 marks Challenging +1.8
5 In this question you must show detailed reasoning. The region bounded by the \(x\)-axis, the \(y\)-axis, the line \(x = 4\) and the curve with equation \(\mathrm { y } = \frac { 15 } { \sqrt { \mathrm { x } ^ { 2 } + 9 } }\) is occupied by a uniform lamina. The centre of mass of the lamina is at the point \(G ( \bar { x } , \bar { y } )\) (see diagram). \includegraphics[max width=\textwidth, alt={}, center]{857eca7f-c42d-49a9-ac39-a2fb5bcb9cd5-4_944_954_598_228}
  1. Show that \(\bar { x } = \frac { 2 } { \ln 3 }\).
  2. Determine the value of \(\bar { y }\). Give your answer correct to \(\mathbf { 3 }\) significant figures. \(P\) is the point on the curved edge of the lamina where \(x = 3\). The lamina is freely suspended from \(P\) and hangs in equilibrium in a vertical plane.
  3. Determine the acute angle that the longest straight edge of the lamina makes with the vertical.