| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2003 |
| Session | November |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Free fall: time or distance |
| Difficulty | Easy -1.3 This is a straightforward SUVAT application question requiring direct substitution into kinematic equations with no problem-solving insight needed. All three parts use standard formulas (v=u+at, s=ut+½at², v²=u²+2as) with given values, making it easier than average and purely procedural. |
| Spec | 3.02h Motion under gravity: vector form |
| Answer | Marks | Guidance |
|---|---|---|
| Speed is 20 m s\(^{-1}\) | B1 | 1 mark |
| For using \(s = \frac{1}{2}gt^2\) with \(45 = \frac{1}{2} \times 10t^2\) | M1 | |
| Time taken is 3 s | A1 | 2 marks |
| For using \(v^2 = u^2 + 2gs\) with \((40^2 = 30^2 + 2 \times 10s)\) | M1 | |
| Distance fallen is 35 m | A1 | 2 marks |
Speed is 20 m s$^{-1}$ | B1 | 1 mark
For using $s = \frac{1}{2}gt^2$ with $45 = \frac{1}{2} \times 10t^2$ | M1 |
Time taken is 3 s | A1 | 2 marks
For using $v^2 = u^2 + 2gs$ with $(40^2 = 30^2 + 2 \times 10s)$ | M1 |
Distance fallen is 35 m | A1 | 2 marks
---2 A stone is released from rest and falls freely under gravity. Find\\
(i) the speed of the stone after 2 s ,\\
(ii) the time taken for the stone to fall a distance of 45 m from its initial position,\\
(iii) the distance fallen by the stone from the instant when its speed is $30 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ to the instant when its speed is $40 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\hfill \mbox{\textit{CAIE M1 2003 Q2 [5]}}