| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2003 |
| Session | November |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Power and driving force |
| Type | Find acceleration given power |
| Difficulty | Moderate -0.5 This is a straightforward application of the power-force-velocity relationship (P=Fv) and Newton's second law (F=ma). Students need to find driving force from power and speed, then use F_net = ma to find resistance. It's a standard two-step M1 mechanics problem requiring direct formula application with no conceptual challenges or problem-solving insight. |
| Spec | 6.02l Power and velocity: P = Fv |
| Answer | Marks | Guidance |
|---|---|---|
| The force is 320 N | B1 | 1 mark |
| For using Newton's second law (3 terms needed) | M1 | |
| \(320 - R = 100 \times 0.5\) | A1 √ | |
| Resistance is 270 N | A1 | 3 marks |
The force is 320 N | B1 | 1 mark
For using Newton's second law (3 terms needed) | M1 |
$320 - R = 100 \times 0.5$ | A1 √ |
Resistance is 270 N | A1 | 3 marks
---1 A motorcycle of mass 100 kg is travelling on a horizontal straight road. Its engine is working at a rate of 8 kW . At an instant when the speed of the motorcycle is $25 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ its acceleration is $0.5 \mathrm {~m} \mathrm {~s} ^ { - 2 }$. Find, at this instant,\\
(i) the force produced by the engine,\\
(ii) the resistance to motion of the motorcycle.
\hfill \mbox{\textit{CAIE M1 2003 Q1 [4]}}