Pre-U Pre-U 9795 Specimen — Question 4 6 marks

Exam BoardPre-U
ModulePre-U 9795 (Pre-U Further Mathematics)
SessionSpecimen
Marks6
TopicSequences and series, recurrence and convergence
TypeAlternating series summation
DifficultyStandard +0.3 This question requires knowing the standard sum formula for cubes and then using algebraic manipulation to separate odd and even terms. While it involves multiple steps, the techniques are straightforward: recall a standard result, split the alternating sum into two parts, and simplify. The algebraic manipulation is routine for Further Maths students, making this slightly easier than average.
Spec4.06a Summation formulae: sum of r, r^2, r^34.06b Method of differences: telescoping series

Write down the sum $$\sum_{n=1}^{2N} n^3$$ in terms of \(N\), and hence find $$1^3 - 2^3 + 3^3 - 4^3 + \ldots - (2N)^3$$ in terms of \(N\), simplifying your answer. [6]

Write down the sum
$$\sum_{n=1}^{2N} n^3$$
in terms of $N$, and hence find
$$1^3 - 2^3 + 3^3 - 4^3 + \ldots - (2N)^3$$
in terms of $N$, simplifying your answer. [6]

\hfill \mbox{\textit{Pre-U Pre-U 9795  Q4 [6]}}