OCR H240/02 2017 Specimen — Question 12 5 marks

Exam BoardOCR
ModuleH240/02 (Pure Mathematics and Statistics)
Year2017
SessionSpecimen
Marks5
TopicZ-tests (known variance)
TypeTest using proportion
DifficultyChallenging +1.2 This is a hypothesis testing question requiring students to work backwards from a significance level to find a critical value. It involves calculating a population proportion, setting up a one-tailed test at 2.5% level, using normal approximation to binomial, and solving for m from the critical region inequality. While it requires multiple steps and reverse-engineering the usual hypothesis test process, the techniques are all standard S1 content with no novel conceptual leaps required.
Spec2.04d Normal approximation to binomial2.05b Hypothesis test for binomial proportion

The table shows information for England and Wales, taken from the UK 2011 census.
Total populationNumber of children aged 5-17
56 075 9128 473 617
A random sample of 10 000 people in another country was chosen in 2011, and the number, \(m\), of children aged 5-17 was noted. It was found that there was evidence at the 2.5% level that the proportion of children aged 5-17 in the same year was higher than in the UK. Unfortunately, when the results were recorded the value of \(m\) was omitted. Use an appropriate normal distribution to find an estimate of the smallest possible value of \(m\). [5]

The table shows information for England and Wales, taken from the UK 2011 census.

\begin{center}
\begin{tabular}{|l|c|}
\hline
Total population & Number of children aged 5-17 \\
\hline
56 075 912 & 8 473 617 \\
\hline
\end{tabular}
\end{center}

A random sample of 10 000 people in another country was chosen in 2011, and the number, $m$, of children aged 5-17 was noted.
It was found that there was evidence at the 2.5% level that the proportion of children aged 5-17 in the same year was higher than in the UK.
Unfortunately, when the results were recorded the value of $m$ was omitted.

Use an appropriate normal distribution to find an estimate of the smallest possible value of $m$. [5]

\hfill \mbox{\textit{OCR H240/02 2017 Q12 [5]}}