OCR FS1 AS 2021 June — Question 2 8 marks

Exam BoardOCR
ModuleFS1 AS (Further Statistics 1 AS)
Year2021
SessionJune
Marks8
TopicDiscrete Probability Distributions
TypeMultiple unknowns from expectation and variance
DifficultyStandard +0.3 This is a straightforward probability distribution question requiring students to find x using the sum of probabilities equals 1, then calculate E(W) and E(W²) to find variance using the standard formula. Part (b) tests basic knowledge of variance properties. While it involves solving a quadratic and multiple calculation steps (7 marks), the techniques are all standard FS1 content with no novel problem-solving required, making it slightly easier than average.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables5.02c Linear coding: effects on mean and variance

The probability distribution for the discrete random variable \(W\) is given in the table.
\(w\)1234
\(P(W = w)\)0.250.36\(x\)\(x^2\)
  1. Show that \(\text{Var}(W) = 0.8571\). [7]
  2. Find \(\text{Var}(3W + 6)\). [1]

The probability distribution for the discrete random variable $W$ is given in the table.

\begin{tabular}{|c|c|c|c|c|}
\hline
$w$ & 1 & 2 & 3 & 4 \\
\hline
$P(W = w)$ & 0.25 & 0.36 & $x$ & $x^2$ \\
\hline
\end{tabular}

\begin{enumerate}[label=(\alph*)]
\item Show that $\text{Var}(W) = 0.8571$. [7]

\item Find $\text{Var}(3W + 6)$. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR FS1 AS 2021 Q2 [8]}}