SPS SPS SM 2025 February — Question 5 7 marks

Exam BoardSPS
ModuleSPS SM (SPS SM)
Year2025
SessionFebruary
Marks7
TopicIndefinite & Definite Integrals
TypeFind curve from gradient
DifficultyStandard +0.3 This question requires integrating a simple linear function to find the curve equation, using a point to find the constant, then solving a quadratic equation where the curve meets a line. All steps are routine A-level techniques with no conceptual challenges, making it slightly easier than average.
Spec1.02c Simultaneous equations: two variables by elimination and substitution1.08a Fundamental theorem of calculus: integration as reverse of differentiation

A curve has the following properties: • The gradient of the curve is given by \(\frac{dy}{dx} = -2x\). • The curve passes through the point \((4, -13)\). Determine the coordinates of the points where the curve meets the line \(y = 2x\). [7]

A curve has the following properties:

• The gradient of the curve is given by $\frac{dy}{dx} = -2x$.

• The curve passes through the point $(4, -13)$.

Determine the coordinates of the points where the curve meets the line $y = 2x$. [7]

\hfill \mbox{\textit{SPS SPS SM 2025 Q5 [7]}}