SPS SPS FM Pure 2024 February — Question 3 6 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2024
SessionFebruary
Marks6
TopicRoots of polynomials
TypeComplex roots with real coefficients
DifficultyStandard +0.3 This is a standard Further Maths complex roots question requiring knowledge that complex roots come in conjugate pairs for real coefficient polynomials. Students must find the conjugate root (1+3i), form the quadratic factor (z-(1-3i))(z-(1+3i)) = z²-2z+10, then divide the quartic to find the other quadratic factor. While it requires multiple steps and careful algebra, it follows a well-practiced procedure with no novel insight needed. Slightly easier than average due to the structured guidance.
Spec4.02g Conjugate pairs: real coefficient polynomials4.02j Cubic/quartic equations: conjugate pairs and factor theorem

It is given that \(1 - 3i\) is one root of the quartic equation $$z^4 - 2z^3 + pz^2 + rz + 80 = 0$$ where \(p\) and \(r\) are real numbers.
  1. Express \(z^4 - 2z^3 + pz^2 + rz + 80\) as the product of two quadratic factors with real coefficients. [4 marks]
  2. Find the value of \(p\) and the value of \(r\). [2 marks]

It is given that $1 - 3i$ is one root of the quartic equation
$$z^4 - 2z^3 + pz^2 + rz + 80 = 0$$
where $p$ and $r$ are real numbers.

\begin{enumerate}[label=(\alph*)]
\item Express $z^4 - 2z^3 + pz^2 + rz + 80$ as the product of two quadratic factors with real coefficients. [4 marks]
\item Find the value of $p$ and the value of $r$. [2 marks]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2024 Q3 [6]}}