SPS SPS SM Pure 2023 September — Question 10 12 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2023
SessionSeptember
Marks12
TopicTangents, normals and gradients
TypeOptimization with constraints
DifficultyStandard +0.3 This is a standard optimization problem requiring volume formula for a prism with sector cross-section, surface area calculation, and basic calculus (differentiation to find minimum). The algebra is straightforward, and the method is a routine textbook exercise in applied calculus, making it slightly easier than average for A-level.
Spec1.02z Models in context: use functions in modelling1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta1.07n Stationary points: find maxima, minima using derivatives1.07o Increasing/decreasing: functions using sign of dy/dx

\includegraphics{figure_10} The figure above shows solid right prism of height \(h\) cm. The cross section of the prism is a circular sector of radius \(r\) cm, subtending an angle of 2 radians at the centre.
  1. Given that the volume of the prism is 1000 cm\(^3\), show clearly that $$S = 2r^2 + \frac{4000}{r},$$ where \(S\) cm\(^2\) is the total surface area of the prism. [5]
  2. Hence determine the value of \(r\) and the value of \(h\) which make \(S\) least, fully justifying your answer. [7]

\includegraphics{figure_10}

The figure above shows solid right prism of height $h$ cm.

The cross section of the prism is a circular sector of radius $r$ cm, subtending an angle of 2 radians at the centre.

\begin{enumerate}[label=(\alph*)]
\item Given that the volume of the prism is 1000 cm$^3$, show clearly that
$$S = 2r^2 + \frac{4000}{r},$$
where $S$ cm$^2$ is the total surface area of the prism. [5]

\item Hence determine the value of $r$ and the value of $h$ which make $S$ least, fully justifying your answer. [7]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM Pure 2023 Q10 [12]}}