SPS SPS SM Pure 2023 June — Question 12 6 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2023
SessionJune
Marks6
TopicStandard trigonometric equations
TypeDeduce related solution
DifficultyStandard +0.3 Part (a) requires using the Pythagorean identity to convert to a quadratic in sin x, then solving—a standard technique. Part (b) is a straightforward substitution using the solutions from (a). This is a typical multi-part trigonometric equation question requiring familiar methods but no novel insight, making it slightly easier than average.
Spec1.02f Solve quadratic equations: including in a function of unknown1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

  1. Solve, for \(-180° \leq x < 180°\), the equation $$3 \sin^2 x + \sin x + 8 = 9 \cos^2 x$$ giving your answers to 2 decimal places. [4]
  2. Hence find the smallest positive solution of the equation $$3\sin^2(2\theta - 30°) + \sin(2\theta - 30°) + 8 = 9 \cos^2(2\theta - 30°)$$ giving your answer to 2 decimal places. [2]

(a) Solve, for $-180° \leq x < 180°$, the equation

$$3 \sin^2 x + \sin x + 8 = 9 \cos^2 x$$

giving your answers to 2 decimal places. [4]

(b) Hence find the smallest positive solution of the equation

$$3\sin^2(2\theta - 30°) + \sin(2\theta - 30°) + 8 = 9 \cos^2(2\theta - 30°)$$

giving your answer to 2 decimal places. [2]

\hfill \mbox{\textit{SPS SPS SM Pure 2023 Q12 [6]}}