SPS SPS SM Pure 2023 June — Question 11 10 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2023
SessionJune
Marks10
TopicComposite & Inverse Functions
TypeFind inverse function
DifficultyStandard +0.3 This is a multi-part function question covering range, inverse functions, and composition. Parts (a)-(c) are standard A-level techniques: finding range of a rational function, algebraic manipulation for inverse, and verifying a composition. Part (d) requires connecting previous parts but is straightforward once you recognize ff(x) = 7/2 is outside the range found in (a). Slightly easier than average due to the guided structure and routine methods, though the composition verification requires careful algebra.
Spec1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

The function \(f\) is defined by $$f(x) = \frac{12x}{3x + 4} \quad x \in \mathbb{R}, x \geq 0$$
  1. Find the range of \(f\). [2]
  2. Find \(f^{-1}\). [3]
  3. Show, for \(x \in \mathbb{R}, x \geq 0\), that $$ff(x) = \frac{9x}{3x + 1}$$ [3]
  4. Show that \(ff(x) = \frac{7}{2}\) has no solutions. [2]

The function $f$ is defined by

$$f(x) = \frac{12x}{3x + 4} \quad x \in \mathbb{R}, x \geq 0$$

(a) Find the range of $f$. [2]

(b) Find $f^{-1}$. [3]

(c) Show, for $x \in \mathbb{R}, x \geq 0$, that

$$ff(x) = \frac{9x}{3x + 1}$$ [3]

(d) Show that $ff(x) = \frac{7}{2}$ has no solutions. [2]

\hfill \mbox{\textit{SPS SPS SM Pure 2023 Q11 [10]}}