SPS SPS FM 2021 April — Question 7 6 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2021
SessionApril
Marks6
TopicProof by induction
TypeProve matrix power formula
DifficultyStandard +0.3 This is a standard matrix induction proof with straightforward matrix multiplication. The base case is trivial, and the inductive step requires only routine 2×2 matrix multiplication and simple algebraic manipulation of the formula 3(2^(k+1) - 1) = 3(2·2^k - 1). While it's a Further Maths question, it's a textbook example of proof by induction with matrices, requiring no novel insight or complex reasoning—slightly easier than average overall.
Spec4.01a Mathematical induction: construct proofs4.03b Matrix operations: addition, multiplication, scalar

$$\mathbf{M} = \begin{pmatrix} 2 & 3 \\ 0 & 1 \end{pmatrix}.$$ Prove by induction that \(\mathbf{M}^n = \begin{pmatrix} 2^n & 3(2^n - 1) \\ 0 & 1 \end{pmatrix}\), for all positive integers \(n\). [6]

$$\mathbf{M} = \begin{pmatrix} 2 & 3 \\ 0 & 1 \end{pmatrix}.$$

Prove by induction that $\mathbf{M}^n = \begin{pmatrix} 2^n & 3(2^n - 1) \\ 0 & 1 \end{pmatrix}$, for all positive integers $n$. [6]

\hfill \mbox{\textit{SPS SPS FM 2021 Q7 [6]}}