SPS SPS FM 2021 April — Question 1 11 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2021
SessionApril
Marks11
TopicDifferentiating Transcendental Functions
TypeDifferentiate exponential functions
DifficultyModerate -0.3 This is a standard calculus techniques question testing routine differentiation (chain rule, product rule, quotient rule) and integration (substitution, polynomial division). All parts follow textbook patterns with no problem-solving required, but the variety of techniques and algebraic manipulation needed (especially parts i(d) and ii(b)) elevate it slightly above pure recall, placing it just below average difficulty.
Spec1.07j Differentiate exponentials: e^(kx) and a^(kx)1.07l Derivative of ln(x): and related functions1.07q Product and quotient rules: differentiation1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08j Integration using partial fractions

  1. Differentiate the following with respect to \(x\), simplifying your answers fully
    1. \(y = e^{3x} + \ln 2x\) [1]
    2. \(y = (5 + x^2)^{\frac{3}{2}}\) [1]
    3. \(y = \frac{2x}{(5-3x^2)^{\frac{1}{2}}}\) [2]
    4. \(y = e^{-\frac{3}{x}} \ln(1 + x^3)\) [2]
  2. Integrate with respect to \(x\)
    1. \(\frac{7}{(2x-5)^8} - \frac{3}{2x-5}\) [2]
    2. \(\frac{4x^2+5x-3}{2x-5}\) [3]

\begin{enumerate}[label=(\roman*)]
\item Differentiate the following with respect to $x$, simplifying your answers fully

\begin{enumerate}[label=(\alph*)]
\item $y = e^{3x} + \ln 2x$ [1]

\item $y = (5 + x^2)^{\frac{3}{2}}$ [1]

\item $y = \frac{2x}{(5-3x^2)^{\frac{1}{2}}}$ [2]

\item $y = e^{-\frac{3}{x}} \ln(1 + x^3)$ [2]
\end{enumerate}

\item Integrate with respect to $x$

\begin{enumerate}[label=(\alph*)]
\item $\frac{7}{(2x-5)^8} - \frac{3}{2x-5}$ [2]

\item $\frac{4x^2+5x-3}{2x-5}$ [3]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM 2021 Q1 [11]}}