WJEC Further Unit 4 2022 June — Question 2 4 marks

Exam BoardWJEC
ModuleFurther Unit 4 (Further Unit 4)
Year2022
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex numbers 2
TypeDirect nth roots: roots with geometric or algebraic follow-up
DifficultyStandard +0.8 This question requires converting a complex number to modulus-argument form, applying De Moivre's theorem to find fourth roots, and recognizing that all roots share the same modulus (which defines the circle's radius). While the steps are standard for Further Maths, the calculation involves non-trivial values (modulus 2√3, argument -π/6) and requires careful execution across multiple techniques, placing it moderately above average difficulty.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02f Convert between forms: cartesian and modulus-argument4.02r nth roots: of complex numbers

When plotted on an Argand diagram, the four fourth roots of the complex number \(9 - 3\sqrt{3}i\) lie on a circle. Find the equation of this circle. [4]

Let \(z^4 = 9 - 3\sqrt{3}i\)
AnswerMarks Guidance
\(z^4 = \sqrt{9^2 + (3\sqrt{3})^2} = \sqrt{108} = 6\sqrt{3}\)
Finding the radius of the circleM1 FT their \(
e.g. Radius of circle = \(\sqrt[4]{108}\) or \(108^{\frac{1}{8}} = 1.795...\)A1
Circle: \(x^2 + y^2 = 3.22\) or \(1.795^2\)A1 FT their radius. Allow \(1.8^2\). Allow \(
Let $z^4 = 9 - 3\sqrt{3}i$

$|z^4| = \sqrt{9^2 + (3\sqrt{3})^2} = \sqrt{108} = 6\sqrt{3}$ | B1 | si

Finding the radius of the circle | M1 | FT their $|z^4|$
e.g. Radius of circle = $\sqrt[4]{108}$ or $108^{\frac{1}{8}} = 1.795...$ | A1 | 
Circle: $x^2 + y^2 = 3.22$ or $1.795^2$ | A1 | FT their radius. Allow $1.8^2$. Allow $|z| = 108^{1/8}$

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When plotted on an Argand diagram, the four fourth roots of the complex number $9 - 3\sqrt{3}i$ lie on a circle. Find the equation of this circle. [4]

\hfill \mbox{\textit{WJEC Further Unit 4 2022 Q2 [4]}}