WJEC Unit 4 2019 June — Question 10 9 marks

Exam BoardWJEC
ModuleUnit 4 (Unit 4)
Year2019
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeProjectile clearing obstacle
DifficultyStandard +0.3 This is a standard A-level mechanics projectile motion question requiring routine application of SUVAT equations in vector form. Part (a) uses v = u + at to find final velocity, part (b) finds position using s = ut + ½at², and part (c) asks for basic modeling assumptions—all textbook exercises with no novel problem-solving required. Slightly easier than average due to straightforward structure and given time values.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

A tennis ball is projected with velocity vector \((30\mathbf{i} - 14\mathbf{j})\) ms\(^{-1}\) from a point \(P\) which is at a height of \(2.4\) m vertically above a horizontal tennis court. The ball then passes over a net of height \(0.9\) m, before hitting the ground after \(\frac{4}{7}\) s. The unit vectors \(\mathbf{i}\) and \(\mathbf{j}\) are horizontal and vertical respectively. The origin \(O\) lies on the ground directly below the point \(P\). The base of the net is \(x\) m from \(O\). \includegraphics{figure_10}
  1. Find the speed of the ball when it first hits the ground, giving your answer correct to one decimal place. [3]
  2. After \(\frac{2}{5}\) s, the ball is directly above the net.
    1. Find the position vector of the ball after \(\frac{2}{5}\) s.
    2. Hence determine the value of \(x\) and show that the ball clears the net by approximately \(16\) cm. [4]
  3. In fact, the ball clears the net by only \(4\) cm.
    1. Explain why the observed value is different from the value calculated in (b)(ii).
    2. Suggest a possible improvement to this model. [2]

A tennis ball is projected with velocity vector $(30\mathbf{i} - 14\mathbf{j})$ ms$^{-1}$ from a point $P$ which is at a height of $2.4$ m vertically above a horizontal tennis court. The ball then passes over a net of height $0.9$ m, before hitting the ground after $\frac{4}{7}$ s.

The unit vectors $\mathbf{i}$ and $\mathbf{j}$ are horizontal and vertical respectively. The origin $O$ lies on the ground directly below the point $P$. The base of the net is $x$ m from $O$.

\includegraphics{figure_10}

\begin{enumerate}[label=(\alph*)]
\item Find the speed of the ball when it first hits the ground, giving your answer correct to one decimal place. [3]

\item After $\frac{2}{5}$ s, the ball is directly above the net.
\begin{enumerate}[label=(\roman*)]
\item Find the position vector of the ball after $\frac{2}{5}$ s.

\item Hence determine the value of $x$ and show that the ball clears the net by approximately $16$ cm. [4]
\end{enumerate}

\item In fact, the ball clears the net by only $4$ cm.
\begin{enumerate}[label=(\roman*)]
\item Explain why the observed value is different from the value calculated in (b)(ii).

\item Suggest a possible improvement to this model. [2]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 4 2019 Q10 [9]}}