WJEC Unit 4 2019 June — Question 1 5 marks

Exam BoardWJEC
ModuleUnit 4 (Unit 4)
Year2019
SessionJune
Marks5
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Mark schemeDownload PDF ↗
TopicConditional Probability
TypeStandard Bayes with discrete events
DifficultyModerate -0.8 This is a straightforward conditional probability question using the law of total probability and Bayes' theorem. Part (a) requires calculating P(works) = Σ P(works|supplier) × P(supplier) with given values, and part (b) applies Bayes' theorem directly. The arithmetic is simple, and both parts follow standard S1/S2 procedures with no conceptual challenges or problem-solving required.
Spec2.03c Conditional probability: using diagrams/tables2.03d Calculate conditional probability: from first principles

Val buys electrical components from one of 3 suppliers \(A\), \(B\), \(C\), in the ratio \(2:1:7\). The probability that the component is faulty is \(0.33\) for \(A\), \(0.45\) for \(B\) and \(0.05\) for \(C\). Val selects a component at random.
  1. Find the probability that the component works. [3]
  2. Given that the component works, find the probability that Val bought the component from supplier \(B\). [2]

Question 1:
AnswerMarks
10
Question 1:
1 | 0
Val buys electrical components from one of 3 suppliers $A$, $B$, $C$, in the ratio $2:1:7$. The probability that the component is faulty is $0.33$ for $A$, $0.45$ for $B$ and $0.05$ for $C$. Val selects a component at random.

\begin{enumerate}[label=(\alph*)]
\item Find the probability that the component works. [3]

\item Given that the component works, find the probability that Val bought the component from supplier $B$. [2]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 4 2019 Q1 [5]}}