WJEC Unit 3 2024 June — Question 12 6 marks

Exam BoardWJEC
ModuleUnit 3 (Unit 3)
Year2024
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSmall angle approximation
TypeReciprocal expansion to polynomial form
DifficultyStandard +0.3 This question tests small angle approximations and binomial expansion of (1+x)^(-1), both standard C3/C4 techniques. Part (a) is straightforward substitution of cos θ ≈ 1 - θ²/2 and sin θ ≈ θ. Part (b) requires recognizing the form for binomial expansion and expanding to θ² terms—routine application with no novel insight required, though the algebraic manipulation earns it a slightly above-average rating.
Spec1.05e Small angle approximations: sin x ~ x, cos x ~ 1-x^2/2, tan x ~ x

  1. Given that \(\theta\) is small, show that \(2\cos\theta + \sin\theta - 1 \approx 1 + \theta - \theta^2\). [2]
  2. Hence, when \(\theta\) is small, show that $$\frac{1}{2\cos\theta + \sin\theta - 1} \approx 1 + a\theta + b\theta^2,$$ where \(a\), \(b\) are constants to be found. [4]

Question 12:
AnswerMarks
126
Question 12:
12 | 6
\begin{enumerate}[label=(\alph*)]
\item Given that $\theta$ is small, show that $2\cos\theta + \sin\theta - 1 \approx 1 + \theta - \theta^2$. [2]

\item Hence, when $\theta$ is small, show that
$$\frac{1}{2\cos\theta + \sin\theta - 1} \approx 1 + a\theta + b\theta^2,$$
where $a$, $b$ are constants to be found. [4]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 3 2024 Q12 [6]}}