WJEC Unit 3 2024 June — Question 10 14 marks

Exam BoardWJEC
ModuleUnit 3 (Unit 3)
Year2024
SessionJune
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind inverse function
DifficultyStandard +0.3 This is a structured multi-part question on rational functions requiring algebraic manipulation (partial fractions in reverse), range determination from a restricted domain, finding an inverse function, and solving f(x)=f^{-1}(x). While it involves several techniques, each part follows standard A-level procedures with clear scaffolding. The algebra is moderately involved but routine for C3 level, making it slightly easier than average overall.
Spec1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02v Inverse and composite functions: graphs and conditions for existence

The function \(f\) has domain \([4, \infty)\) and is defined by $$f(x) = \frac{2(3x + 1)}{x^2 - 2x - 3} + \frac{x}{x + 1}.$$
  1. Show that \(f(x) = \frac{x + 2}{x - 3}\). [4]
  2. Determine the range of \(f(x)\). [2]
  3. Find an expression for \(f^{-1}(x)\) and write down the domain and range of \(f^{-1}\). [4]
  4. Find the value of \(x\) when \(f(x) = f^{-1}(x)\). [4]

Question 10:
AnswerMarks
1014
Question 10:
10 | 14
The function $f$ has domain $[4, \infty)$ and is defined by
$$f(x) = \frac{2(3x + 1)}{x^2 - 2x - 3} + \frac{x}{x + 1}.$$

\begin{enumerate}[label=(\alph*)]
\item Show that $f(x) = \frac{x + 2}{x - 3}$. [4]

\item Determine the range of $f(x)$. [2]

\item Find an expression for $f^{-1}(x)$ and write down the domain and range of $f^{-1}$. [4]

\item Find the value of $x$ when $f(x) = f^{-1}(x)$. [4]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 3 2024 Q10 [14]}}