WJEC Unit 3 2024 June — Question 4 6 marks

Exam BoardWJEC
ModuleUnit 3 (Unit 3)
Year2024
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFunction Transformations
TypeModulus function transformations
DifficultyModerate -0.8 This is a straightforward modulus function question requiring basic graph sketching and simple transformations. Part (a) involves plotting y = |3x + 4| (finding intercepts at x = -4/3 and y = 4), while part (b) applies a vertical scaling by 1/2 and translation down 6 units. Both parts are routine exercises with no problem-solving or novel insight required, making it easier than average but not trivial since it involves multiple steps and transformation application.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02w Graph transformations: simple transformations of f(x)

A function \(f\) is given by \(f(x) = |3x + 4|\).
  1. Sketch the graph of \(y = f(x)\). Clearly label the coordinates of the point \(A\), where the graph meets the \(x\)-axis, and the coordinates of the point \(B\), where the graph cuts the \(y\)-axis. [3]
  2. On a separate set of axes, sketch the graph of \(y = \frac{1}{2}f(x) - 6\), where the points \(A\) and \(B\) are transformed to the points \(A'\) and \(B'\). Clearly label the coordinates of the points \(A'\) and \(B'\). [3]

Question 4:
AnswerMarks
46
Question 4:
4 | 6
A function $f$ is given by $f(x) = |3x + 4|$.

\begin{enumerate}[label=(\alph*)]
\item Sketch the graph of $y = f(x)$. Clearly label the coordinates of the point $A$, where the graph meets the $x$-axis, and the coordinates of the point $B$, where the graph cuts the $y$-axis. [3]

\item On a separate set of axes, sketch the graph of $y = \frac{1}{2}f(x) - 6$, where the points $A$ and $B$ are transformed to the points $A'$ and $B'$.
Clearly label the coordinates of the points $A'$ and $B'$. [3]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 3 2024 Q4 [6]}}