WJEC Unit 2 2024 June — Question 10 11 marks

Exam BoardWJEC
ModuleUnit 2 (Unit 2)
Year2024
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTravel graphs
TypeDisplacement-time graph interpretation or sketching
DifficultyModerate -0.8 This is a straightforward kinematics problem using SUVAT equations with clearly defined stages of motion. Part (a) is a simple 'show that' calculation, part (b) requires basic arithmetic and one quadratic equation, and part (c) asks for a standard sketch. The multi-stage structure adds some bookkeeping but no conceptual challenge—this is easier than average A-level content.
Spec3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area3.02d Constant acceleration: SUVAT formulae

A car, starting from rest at a point \(A\), travels along a straight horizontal road towards a point \(B\). The distance between points \(A\) and \(B\) is 1·9 km. Initially, the car accelerates uniformly for 12 seconds until it reaches a speed of 26 ms\(^{-1}\). The car continues at 26 ms\(^{-1}\) for 1 minute, before decelerating at a constant rate of 0·75 ms\(^{-2}\) until it passes the point \(B\).
  1. Show that the car travels 156 m while it is accelerating. [2]
    1. Work out the distance travelled by the car while travelling at a constant speed. [1]
    2. Hence calculate the length of time for which the car is decelerating until it passes the point \(B\). [5]
  2. Sketch a displacement-time graph for the motion of the car between \(A\) and \(B\). [3]

Question 10:
AnswerMarks
1011
Total75
Daily number
of 2nd dose
vaccines
AnswerMarks
(1000s)Midpoint
xFrequency
fPercentage
0 X v ! 100
100 X v ! 200
200 X v ! 300
300 X v ! 400
400 X v ! 500
AnswerMarks
500 X v ! 60050
150
250
350
450
AnswerMarks
5502
8
10
13
26
AnswerMarks
2.
33
.
131
.
164
.
213
.
426
.
33
AnswerMarks Guidance
Total61 100
P
Q
Question
AnswerMarks
numberAdditional page, if required.
Write the question number(s) in the left-hand margin.
Question
AnswerMarks
numberAdditional page, if required.
Write the question number(s) in the left-hand margin.
Question 10:
10 | 11
Total | 75
Daily number
of 2nd dose
vaccines
(1000s) | Midpoint
x | Frequency
f | Percentage
0 X v ! 100
100 X v ! 200
200 X v ! 300
300 X v ! 400
400 X v ! 500
500 X v ! 600 | 50
150
250
350
450
550 | 2
8
10
13
26
2 | .
33
.
131
.
164
.
213
.
426
.
33
Total | 61 | 100
P
Q
Question
number | Additional page, if required.
Write the question number(s) in the left-hand margin.
Question
number | Additional page, if required.
Write the question number(s) in the left-hand margin.
A car, starting from rest at a point $A$, travels along a straight horizontal road towards a point $B$. The distance between points $A$ and $B$ is 1·9 km. Initially, the car accelerates uniformly for 12 seconds until it reaches a speed of 26 ms$^{-1}$. The car continues at 26 ms$^{-1}$ for 1 minute, before decelerating at a constant rate of 0·75 ms$^{-2}$ until it passes the point $B$.

\begin{enumerate}[label=(\alph*)]
\item Show that the car travels 156 m while it is accelerating. [2]

\item \begin{enumerate}[label=(\roman*)]
\item Work out the distance travelled by the car while travelling at a constant speed. [1]

\item Hence calculate the length of time for which the car is decelerating until it passes the point $B$. [5]
\end{enumerate}

\item Sketch a displacement-time graph for the motion of the car between $A$ and $B$. [3]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 2 2024 Q10 [11]}}