WJEC Unit 2 2024 June — Question 8 7 marks

Exam BoardWJEC
ModuleUnit 2 (Unit 2)
Year2024
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeVelocity from acceleration by integration
DifficultyModerate -0.3 This is a straightforward mechanics question requiring application of F=ma, integration to find velocity, and interpretation of velocity/acceleration signs. Part (a) is direct substitution, part (b) is routine integration with a boundary condition, and part (c) requires checking if velocity and acceleration have the same sign. All techniques are standard A-level mechanics with no novel problem-solving required, making it slightly easier than average.
Spec3.03c Newton's second law: F=ma one dimension3.03d Newton's second law: 2D vectors6.06a Variable force: dv/dt or v*dv/dx methods

A particle, of mass 4 kg, moves in a straight line under the action of a single force \(F\) N, whose magnitude at time \(t\) seconds is given by $$F = 12\sqrt{t} - 32 \quad \text{for} \quad t \geqslant 0.$$
  1. Find the acceleration of the particle when \(t = 9\). [2]
  2. Given that the particle has velocity \(-1\text{ms}^{-1}\) when \(t = 4\), find an expression for the velocity of the particle at \(t\) s. [3]
  3. Determine whether the speed of the particle is increasing or decreasing when \(t = 9\). [2]

Question 8:
AnswerMarks
87
Question 8:
8 | 7
A particle, of mass 4 kg, moves in a straight line under the action of a single force $F$ N, whose magnitude at time $t$ seconds is given by
$$F = 12\sqrt{t} - 32 \quad \text{for} \quad t \geqslant 0.$$

\begin{enumerate}[label=(\alph*)]
\item Find the acceleration of the particle when $t = 9$. [2]

\item Given that the particle has velocity $-1\text{ms}^{-1}$ when $t = 4$, find an expression for the velocity of the particle at $t$ s. [3]

\item Determine whether the speed of the particle is increasing or decreasing when $t = 9$. [2]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 2 2024 Q8 [7]}}