Easy -1.2 This is a straightforward vector mechanics question requiring only basic skills: finding magnitude using Pythagoras (speed = √(16+49) = √65), then using inverse tan to find bearing. It's routine A-level mechanics with no problem-solving element, just direct application of standard formulas, making it easier than average.
A ship \(S\) is moving with constant velocity \((4\mathbf{i} - 7\mathbf{j})\text{ms}^{-1}\), where \(\mathbf{i}\) and \(\mathbf{j}\) are unit vectors due east and due north respectively.
Find the speed and direction of \(S\), giving the direction as a three-figure bearing, correct to the nearest degree. [4]
A ship $S$ is moving with constant velocity $(4\mathbf{i} - 7\mathbf{j})\text{ms}^{-1}$, where $\mathbf{i}$ and $\mathbf{j}$ are unit vectors due east and due north respectively.
Find the speed and direction of $S$, giving the direction as a three-figure bearing, correct to the nearest degree. [4]
\hfill \mbox{\textit{WJEC Unit 2 2024 Q6 [4]}}